diff options
Diffstat (limited to '3841/CH19')
-rw-r--r-- | 3841/CH19/EX19.1/Ex19_1.sce | 13 | ||||
-rw-r--r-- | 3841/CH19/EX19.2/Ex19_2.sce | 26 | ||||
-rw-r--r-- | 3841/CH19/EX19.3/Ex19_3.sce | 11 | ||||
-rw-r--r-- | 3841/CH19/EX19.4.1/Ex19_4_1.sce | 14 | ||||
-rw-r--r-- | 3841/CH19/EX19.4/Ex19_4.sce | 12 |
5 files changed, 76 insertions, 0 deletions
diff --git a/3841/CH19/EX19.1/Ex19_1.sce b/3841/CH19/EX19.1/Ex19_1.sce new file mode 100644 index 000000000..3adceb582 --- /dev/null +++ b/3841/CH19/EX19.1/Ex19_1.sce @@ -0,0 +1,13 @@ +clear +//given +//page no 379 +//find the amount heat absourbed by the cooling system +// +hp=300. +F=0.38 +f=19200. +hi=0.30 +Hi=hp*F*f +C=hi*Hi +Cs=C/hp +printf("\n \n heat lost to cooling system %.2f per bhp-hr",Cs) diff --git a/3841/CH19/EX19.2/Ex19_2.sce b/3841/CH19/EX19.2/Ex19_2.sce new file mode 100644 index 000000000..b9b6e8d24 --- /dev/null +++ b/3841/CH19/EX19.2/Ex19_2.sce @@ -0,0 +1,26 @@ +clear +//given +//page no 379 +// +//find the gallons of water it is neccasry to pump +x=160. +h=2600. +t=60. +//part (a) +//water temperaute rise in 15 deg +Cs=x*h +printf("\n part a") +Hcs=Cs/t +//absorbs per minutes is 15 +Aw=Hcs/15. +//gals of water per min 8.33 +G=Aw/8.33 +printf("\n \n amount of water %.2f gpm",Aw) +printf("\n \n amount of water %.2f gpm",G) +printf("\n partb") +//pound of water required to absorb is 45 deg +Aw1=Hcs/45. +//gallon per water required per min 8.33 +G1=Aw1/8.33 +printf("\n \n amount of water required of 45 deg %.2f gpm",Aw1) +printf("\n \n gallon of water required of 45 deg %.2f gpm",G1) diff --git a/3841/CH19/EX19.3/Ex19_3.sce b/3841/CH19/EX19.3/Ex19_3.sce new file mode 100644 index 000000000..ce0666311 --- /dev/null +++ b/3841/CH19/EX19.3/Ex19_3.sce @@ -0,0 +1,11 @@ +clear +//given +// +//page no 389 +//find how many gallons will a 64-inches +//two thirds of 6 is 4 +l=120+4+4 +//from table +//capacity of full tank +Cf=13.93*l +printf("\n \n capacity of full tank %.2f gal",Cf) diff --git a/3841/CH19/EX19.4.1/Ex19_4_1.sce b/3841/CH19/EX19.4.1/Ex19_4_1.sce new file mode 100644 index 000000000..7dec72cf7 --- /dev/null +++ b/3841/CH19/EX19.4.1/Ex19_4_1.sce @@ -0,0 +1,14 @@ +clear +//given +//page no 394 +//find out how much air enter in cylinder +//as th amount water air taken into engine per hour +x=300 +c=3.9 +t=60. +D=1.2*70200./(1000.) +//dust entering +//engine in 1 year +E=D*9.*250. +De=E/7000. +printf("\n \n dust entering engine %.2f ",De) diff --git a/3841/CH19/EX19.4/Ex19_4.sce b/3841/CH19/EX19.4/Ex19_4.sce new file mode 100644 index 000000000..16b15fe4b --- /dev/null +++ b/3841/CH19/EX19.4/Ex19_4.sce @@ -0,0 +1,12 @@ +clear +//given +//how many gallon does the same tank hold of 25 inches +x=25. +y=64 +z=x/y +printf("\n \n gallons does hold %.2f ",z) +//volume fraction +//1783 is last problem got result we are using it same one +Z=0.3611 +Ct=Z*1783. +printf("\n \n content of tank %.2f gal",Ct) |