Added new codeHEADmaster

5 files changed, 76 insertions, 0 deletions

diff --git a/3841/CH19/EX19.1/Ex19_1.sce b/3841/CH19/EX19.1/Ex19_1.sce
new file mode 100644
index 000000000..3adceb582
--- /dev/null
+++ b/3841/CH19/EX19.1/Ex19_1.sce
@@ -0,0 +1,13 @@
+clear
+//given
+//page no 379
+//find the amount heat absourbed by the cooling system
+//
+hp=300.
+F=0.38
+f=19200.
+hi=0.30
+Hi=hp*F*f
+C=hi*Hi
+Cs=C/hp
+printf("\n \n heat lost to cooling system %.2f per bhp-hr",Cs)
diff --git a/3841/CH19/EX19.2/Ex19_2.sce b/3841/CH19/EX19.2/Ex19_2.sce
new file mode 100644
index 000000000..b9b6e8d24
--- /dev/null
+++ b/3841/CH19/EX19.2/Ex19_2.sce
@@ -0,0 +1,26 @@
+clear
+//given
+//page no 379
+//
+//find the gallons of water it is neccasry to pump
+x=160.
+h=2600.
+t=60.
+//part (a)
+//water temperaute rise in 15 deg
+Cs=x*h
+printf("\n part a")
+Hcs=Cs/t
+//absorbs per minutes is 15
+Aw=Hcs/15.
+//gals of water per min 8.33
+G=Aw/8.33
+printf("\n \n amount of water %.2f gpm",Aw)
+printf("\n \n amount of water %.2f gpm",G)
+printf("\n partb")
+//pound of water required to absorb is 45 deg
+Aw1=Hcs/45.
+//gallon per water required per min 8.33
+G1=Aw1/8.33
+printf("\n \n amount of water required of 45 deg %.2f gpm",Aw1)
+printf("\n \n gallon of water required of 45 deg %.2f gpm",G1)
diff --git a/3841/CH19/EX19.3/Ex19_3.sce b/3841/CH19/EX19.3/Ex19_3.sce
new file mode 100644
index 000000000..ce0666311
--- /dev/null
+++ b/3841/CH19/EX19.3/Ex19_3.sce
@@ -0,0 +1,11 @@
+clear
+//given
+//
+//page no 389
+//find how many gallons will a 64-inches
+//two thirds of 6 is 4
+l=120+4+4
+//from table
+//capacity of full tank
+Cf=13.93*l
+printf("\n \n capacity of full tank %.2f gal",Cf)
diff --git a/3841/CH19/EX19.4.1/Ex19_4_1.sce b/3841/CH19/EX19.4.1/Ex19_4_1.sce
new file mode 100644
index 000000000..7dec72cf7
--- /dev/null
+++ b/3841/CH19/EX19.4.1/Ex19_4_1.sce
@@ -0,0 +1,14 @@
+clear
+//given
+//page no 394
+//find out how much air enter in cylinder
+//as th amount water air taken into engine per hour
+x=300
+c=3.9
+t=60.
+D=1.2*70200./(1000.)
+//dust entering
+//engine in 1 year
+E=D*9.*250.
+De=E/7000.
+printf("\n \n dust entering engine  %.2f ",De)
diff --git a/3841/CH19/EX19.4/Ex19_4.sce b/3841/CH19/EX19.4/Ex19_4.sce
new file mode 100644
index 000000000..16b15fe4b
--- /dev/null
+++ b/3841/CH19/EX19.4/Ex19_4.sce
@@ -0,0 +1,12 @@
+clear
+//given
+//how many gallon does the same tank hold of 25 inches
+x=25.
+y=64
+z=x/y
+printf("\n \n gallons does hold %.2f ",z)
+//volume fraction
+//1783 is last problem got result we are using it same one
+Z=0.3611
+Ct=Z*1783.
+printf("\n \n content of tank %.2f gal",Ct)