diff options
Diffstat (limited to '3831/CH1')
| -rw-r--r-- | 3831/CH1/EX1.1/Ex1_1.sce | 13 | ||||
| -rw-r--r-- | 3831/CH1/EX1.2/Ex1_2.sce | 27 | ||||
| -rw-r--r-- | 3831/CH1/EX1.3/Ex1_3.sce | 14 | ||||
| -rw-r--r-- | 3831/CH1/EX1.4/Ex1_4.sce | 15 | ||||
| -rw-r--r-- | 3831/CH1/EX1.5/Ex1_5.sce | 14 | ||||
| -rw-r--r-- | 3831/CH1/EX1.6/Ex1_6.sce | 8 | ||||
| -rw-r--r-- | 3831/CH1/EX1.7/Ex1_7.sce | 21 | ||||
| -rw-r--r-- | 3831/CH1/EX1.8/Ex1_8.sce | 17 | ||||
| -rw-r--r-- | 3831/CH1/EX1.9/Ex1_9.sce | 13 |
9 files changed, 142 insertions, 0 deletions
diff --git a/3831/CH1/EX1.1/Ex1_1.sce b/3831/CH1/EX1.1/Ex1_1.sce new file mode 100644 index 000000000..a64922c00 --- /dev/null +++ b/3831/CH1/EX1.1/Ex1_1.sce @@ -0,0 +1,13 @@ +// Example 1_1
+clc;funcprot(0);
+// Given data
+V_final=120;// mph
+V_initial=85;// mph
+t=5;// seconds
+
+// Calculation
+a=(V_final-V_initial)/t;// miles/(hour/seconds)
+V_initial=V_initial*(5280/3600);// feet/second
+V_final=V_final*(5280/3600);// feet/second
+a=(V_final-V_initial)/t;// The acceleration in ft/s^2
+printf("\nThe acceleration of the car,a=%2.1f ft/s^2",a);
diff --git a/3831/CH1/EX1.2/Ex1_2.sce b/3831/CH1/EX1.2/Ex1_2.sce new file mode 100644 index 000000000..9295a872d --- /dev/null +++ b/3831/CH1/EX1.2/Ex1_2.sce @@ -0,0 +1,27 @@ +// Example 1_2
+clc;funcprot(0);
+// Given data
+T=55;// °F
+
+// Calculation
+// (a)
+T_w=0;// The freezing point of water in °N
+T_wF=32;// The freezing point of water in °F
+T_bh=12;// The temperature of the body in °N
+T_bhF=98.6;// The temperature of the body in °F
+x=T_bh*(1-((T_bhF-T)/(T_bhF-T_wF)));// The temperature in °N
+printf("\n(a)The temperature on the Newton scale,x=%1.2f °N",x);
+// (b)
+T_w=0;// The temperature in °Re
+T_wF=80;// The temperature in °Re
+T_bh=32;// The temperature in °F
+T_bhF=212;// The temperature in °F
+r=T_wF*(1-((T_bhF-T)/(T_bhF-T_bh)));// The temperature in °Re
+printf("\n(b)The temperature on the Reaumur scale,r=%2.1f °Re",r);
+// (c)
+T_w=273.15;// The temperature in K
+T_wF=373.15;// The temperature in K
+T_bh=32;// The temperature in °F
+T_bhF=212;// The temperature in °F
+z=T_wF-((T_wF-T_w)*(((T_bhF-T)/(T_bhF-T_bh))));// The temperature in K
+printf("\n(c)The Kelvin temperature,z=%3.1f K",z);
diff --git a/3831/CH1/EX1.3/Ex1_3.sce b/3831/CH1/EX1.3/Ex1_3.sce new file mode 100644 index 000000000..2f36ecbcd --- /dev/null +++ b/3831/CH1/EX1.3/Ex1_3.sce @@ -0,0 +1,14 @@ +// Example 1_3
+clc;funcprot(0);
+// Given data
+g_c=32.174;// ft/s^2
+F=1;// lbf
+m=1;// lbm
+
+// Solution
+onechunk=1;// (lbf.s^2)/lbm
+// In the Engineering English units system, 1 lbf accelerates 1 lbm at a rate of
+a=(F*g_c)/m;// ft/s^2
+onechunk=32.174;// ft/s^2
+onechunk=32.174/3.281;// m
+printf("\n 1 chunk=%1.3f m",onechunk);
diff --git a/3831/CH1/EX1.4/Ex1_4.sce b/3831/CH1/EX1.4/Ex1_4.sce new file mode 100644 index 000000000..aaa40e7b1 --- /dev/null +++ b/3831/CH1/EX1.4/Ex1_4.sce @@ -0,0 +1,15 @@ +// Example 1_4
+clc;funcprot(0);
+// Given data
+W=25000;// Weight in lbf
+V=5000;// mph
+g=32.174;// ft/s^2
+g_orbit=2.50;// ft/s^2
+
+// Calculation
+// (a)
+g_c=32.174;// ft/s^2
+// (b)
+m=(W*g_c)/g;// The mass in lbm
+W_orbit=(m*g_orbit)/g_c;// lbf
+printf("\n(a)The value of g_c in this orbit,g_c=%2.3f ft/s^2 \n(b)The weight in Earth orbit,W_orbit=%4.0f lbf",g_c,W_orbit);
diff --git a/3831/CH1/EX1.5/Ex1_5.sce b/3831/CH1/EX1.5/Ex1_5.sce new file mode 100644 index 000000000..817f351d9 --- /dev/null +++ b/3831/CH1/EX1.5/Ex1_5.sce @@ -0,0 +1,14 @@ +// Example 1_5
+clc;funcprot(0);
+// Given data
+D=0.07;// The diameter in m
+R=D/2;// The radius in m
+h=0.15;// The height in m
+L=(3/4)*h;// m
+rho=1000;// The density in kg/m^3
+M=18;// kg/kg mole
+
+// Calculation
+m=(%pi*R^2*L)*rho;// The mass of water in the glass in kg
+n=m/M;// The number of moles in kg moles
+printf("\nThe number of kilogram moles of water in the glass,n=%0.3f kgmole",n);
diff --git a/3831/CH1/EX1.6/Ex1_6.sce b/3831/CH1/EX1.6/Ex1_6.sce new file mode 100644 index 000000000..af887a45f --- /dev/null +++ b/3831/CH1/EX1.6/Ex1_6.sce @@ -0,0 +1,8 @@ +// Example 1_6
+clc;funcprot(0);
+// Given data
+D=2.5;// The inside diameter of a circular water pipe in inches
+
+// Calculation
+A=(%pi*D^2)/4;// in^2
+printf("\nThe cross-sectional area of the pipe,A=%1.4f in^2",A);
diff --git a/3831/CH1/EX1.7/Ex1_7.sce b/3831/CH1/EX1.7/Ex1_7.sce new file mode 100644 index 000000000..757057a86 --- /dev/null +++ b/3831/CH1/EX1.7/Ex1_7.sce @@ -0,0 +1,21 @@ +// Example 1_7
+clc;funcprot(0);
+// Given data
+W=2000;// lbf
+F=W;// lbf
+Z=8.00;// ft
+g_c=1;// Dimensionless
+g=9.81;// m/s^2
+
+// Calculation
+m=((F/0.2248)*g_c)/(g);// kg
+Z=Z/3.281;// m
+PE=(m*g*Z)/g_c;// kJ
+// In the Engineering English units system, we have
+Z=8.00;// m
+g_c=32.174;// lbm.ft/lbf.s^2
+g=32.174;// ft/s^2
+m=(F*g_c)/g;// lbm
+PE=(m*g*Z)/g_c;// ft.lbf
+PE=PE/778.17;// Btu
+printf("\nThe potential energy of an automobile,PE=%2.1f Btu",PE);
diff --git a/3831/CH1/EX1.8/Ex1_8.sce b/3831/CH1/EX1.8/Ex1_8.sce new file mode 100644 index 000000000..68ed87868 --- /dev/null +++ b/3831/CH1/EX1.8/Ex1_8.sce @@ -0,0 +1,17 @@ +// Example 1_8
+clc;funcprot(0);
+// Given data
+V_ft=3000;// ft/s
+m=10.0;// grams
+g_c=1;// Dimensionless
+
+// Calculation
+m=m/1000;// kg
+V=V_ft/3.281;// m/s
+KE=(m*V_ft^2)/(2*g_c);// kJ
+m=(m*2.205);// lbm
+// In the Engineering English units system, we have
+g_c=32.174;// lbm.ft/(lbf.s^2)
+KE=(m*V_ft^2)/(2*g_c);// ft.lbf
+KE=KE/778.17;// Btu
+printf("\nThe translational kinetic energy of a bullet,KE=%1.2f Btu",KE)
diff --git a/3831/CH1/EX1.9/Ex1_9.sce b/3831/CH1/EX1.9/Ex1_9.sce new file mode 100644 index 000000000..803db7236 --- /dev/null +++ b/3831/CH1/EX1.9/Ex1_9.sce @@ -0,0 +1,13 @@ +// Example 1_9
+clc;funcprot(0);
+// Given data
+m=10.0;// lbm
+omega=1800;// rpm
+d=4.00;// inches
+R=d/2;// inches
+g_c=32.174;// lbm.ft/lbf.s^2
+
+// Calculation
+I=(m*(R/12)^2)/2;// lbm.ft^2
+KE_rot=(I*((2*%pi*omega)/60)^2)/(2*g_c);// lbf
+printf("\nThe rotational kinetic energy in the armature of an electric motor,KE_rot=%2.1f ft.lbf",KE_rot);
|