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+// Example 1_3
+clc;funcprot(0);
+// Given data
+g_c=32.174;// ft/s^2
+F=1;// lbf
+m=1;// lbm
+
+// Solution
+onechunk=1;// (lbf.s^2)/lbm
+// In the Engineering English units system, 1 lbf accelerates 1 lbm at a rate of
+a=(F*g_c)/m;// ft/s^2
+onechunk=32.174;// ft/s^2
+onechunk=32.174/3.281;// m
+printf("\n 1 chunk=%1.3f m",onechunk);