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+//Example 3_20 page no:240
+clc;
+//given
+floor_area = 6*6;//in m^2
+ceiling_area = 6*6;//in m^2
+temp = 18;//in C
+wall_AB = 6*3;//in m^2
+cavity = 0.4;//in m
+win_len = 1.2;//in m
+win_width = 1.8;//in m
+external_temp = 1.5;//in C
+//calculating heat losses from walls
+ceiling_loss = ceiling_area * 12.288 * 10^3 * (temp - external_temp);
+wall_AB_loss = 2*(temp - 2.16)*3.885*10^3*(temp - external_temp);
+win_area_loss = 2 * 2.16 *23.1*10^3*(temp - external_temp);
+wall_C_loss = 18*8.18*10^3*(18-12);
+tot_heat_loss = ceiling_loss + wall_AB_loss + win_area_loss + wall_C_loss;
+vol_air_perH = 6*6*3*1.5;
+heat_loss_perH = 1.22 *10^3 * 162 * (18-1.5);
+heat_loss_perH = heat_loss_perH/(776.19);
+tot_vol = 108;
+heat_perM = heat_loss_perH/tot_vol;
+disp(heat_perM,"the heat required to maintain a temperature of 18C in an office is (in W/m^3)");