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+//Book name: Fundamentals of electrical drives by Mohamad A. El- Sharkawi 
+//chapter 5
+//example 5.3
+//edition 1
+//publisher and place:Nelson Engineering
+clc;
+clear;
+l=50;//load in hp
+f=60;//frequency in hertz
+V=440;//voltage of the motor in volts
+p=4;//Number of poles of the motor
+Tmax=2.5;//maximum torque of the motor
+T=1;//motor torque
+smax=0.1;//maximum slip
+ns=(120*f)/p;//synchronous speed in rpm
+disp('a). Motor speed :')
+s=(T/Tmax)*(smax/2);//the equation is obtained from the equation T=3V^2s/wsR2
+n=ns*(1-s);//speed of the motor in rpm
+disp(n,'The speed of the motor at full load in rpm is')
+disp('b).Copper loss of the rotor')
+Pd=l/1.34;//power developed  or Pout in kilowatt
+Pcu2=Pd*(s/(1-s));//copper loss in kilowatt which is obtained from two equationsPcu2=Pg*s,Pd=Pg*(1-s)
+Pcu=Pcu2*10^3;//copper loss in watt
+disp(Pcu,'The copper loss of the rotor in watt is')
+disp('c).Starting torque')
+//At starting slip s=1
+omega=(2*%pi*n)/f;
+Pout=Pd*10^3;//Pout value in watts
+Tst=(smax^(2)*Pout)/(s*omega);
+disp(Tst,'The starting torque in Nm is')
+//The answers vary due to round off error