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+//Book name: Fundamentals of electrical drives by Mohamad A. El- Sharkawi
+//chapter 3
+//example 3.9
+//edition 1
+//publisher and place:Nelson Engineering
+clc;
+clear;
+Vab=208;//source voltage in volts
+Vs=Vab/3^(1/2);//rms voltage in volts
+Vm=Vs*2^(1/2);//maximum peak voltage in volts
+disp('a)To find maximum average voltage across the load:')
+Vavemax=(3*3^(1/2)*Vm)/%pi;
+disp(Vavemax,'maximum average voltage across the load')
+disp('b)To find the triggering angle at the average voltage of the load:')
+xold=1;//assumed value 
+c=30;//constant value
+x=asind((%pi/(3*sqrt(3)))-(cosd(xold+c)));
+err=100;//assumed value
+while(err>0.0001)
+    xnew=asind((%pi/(3*sqrt(3)))-(cosd(x+c)));
+    x=xnew;
+    err=abs(xnew-xold);
+    xold=x;
+   end
+disp(x,'The triggering angle in degree is')
+disp('c)To find load voltage when the triggering angle is -30 degree :')
+Vave=(3*3^(1/2)*Vm)/(2*%pi);
+disp(Vave,'Load voltage when the triggering angle is -30 degree in volt is')
+//The part (b) answer given in the book is wrong