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+//Book name: Fundamentals of electrical drives by Mohamad A. El- Sharkawi
+//chapter 3
+//example 3.6
+//edition 1
+//publisher and place:Nelson Engineering
+clc;
+clear;
+R=10;//resistance of the load in ohm
+L=0.03;//inductance in H
+Vrms=100;//source voltage in volt
+f=60;//frequency in Hz
+alpha=60;//triggering angle in degree
+omega=2*%pi*f;
+tau=L/R;
+Q=atand((omega*L)/R);
+//iteration method
+xold=1;//assumed value 
+x=Q+asind(sind(Q-alpha)*exp((-1)*(((xold-alpha)*(%pi/180))/(omega*tau))));
+err=10;//assumed value
+while(err>0.01)
+    xnew=Q+asind(sind(Q-alpha)*exp((-1)*((x-alpha)*(%pi/180)/(omega*tau))));
+    x=xnew;
+    err=abs(xnew-xold);
+    xold=x;
+   end
+disp(x,'The value of beta in degree is')
+r=x-alpha;
+disp(r,'The conduction period in degree is ')
+//The answer given in the book is wrong.While using the book answer both LHS and RHS are not equal.