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+//Book Name:Fundamentals of Electrical Engineering
+//Author:Rajendra Prasad
+//Publisher: PHI Learning Private Limited
+//Edition:Third ,2014
+
+//Ex9_8.sce.
+
+clc;
+clear;
+VI1=10e6;
+phi1=acosd(0.75);
+phip=acosd(0.9);
+phic=90-asind(7/100); //given loss is 7% of KVA output
+KVAc=VI1*(((sind(phi1)*cosd(phip))-(cosd(phi1)*sind(phip)))/((sind(phic)*cosd(phip))+(cosd(phic)*sind(phip))))*1e-3;
+MVAc=KVAc*1e-3;
+printf("\n The capacity of the synchronous condenser= %1.2f MVA",MVAc)