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+//Book Name:Fundamentals of Electrical Engineering
+//Author:Rajendra Prasad
+//Publisher: PHI Learning Private Limited
+//Edition:Third ,2014
+
+//Ex1_8.sce.
+
+clc;
+clear;
+V=200;         //suply voltage in volts
+R1=0.3e6;     //resistance value in ohms
+R2=0.5e6;     //resistance value in ohms
+C=10e-6;      //capacitance value in farad
+t1=5;         //time seconds
+t2=2.5;       //time in seconds
+
+//case1
+printf("\n (a)")
+v=V*(1-exp(-(t1/(R1*C))));
+printf("\n  The voltage across capacitor when k1 is opened=%3.3f V",v)
+//case2
+printf("\n (b)")
+Im=(v/R2);
+printf("\n  Initial value of discharge current=%1.5f mA",Im*1e3)
+//case3
+printf("\n (c)")
+i=-Im*exp(-(t2/(R2*C)));
+printf("\n  The value of discharge current at 2.5 seconds=%1.3f mA",i*1e3)
+//case4
+printf("\n (d)")
+Vc=v/(R2*C);
+printf("\n  Initial rate of decay of capacitor voltage=%2.3f V/s",Vc)
+//case5
+printf("\n (e)")
+E=(1/2)*(C*v^2);
+printf("\n  The energy dissipated in resistor=%1.4f J",E)