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-rw-r--r--3776/CH5/EX5.1/Ex5_1.sce25
-rw-r--r--3776/CH5/EX5.2/Ex5_2.sce22
-rw-r--r--3776/CH5/EX5.3/Ex5_3.sce27
-rw-r--r--3776/CH5/EX5.4/Ex5_4.sce35
-rw-r--r--3776/CH5/EX5.9/Ex5_9.sce30
5 files changed, 139 insertions, 0 deletions
diff --git a/3776/CH5/EX5.1/Ex5_1.sce b/3776/CH5/EX5.1/Ex5_1.sce
new file mode 100644
index 000000000..f223bc45a
--- /dev/null
+++ b/3776/CH5/EX5.1/Ex5_1.sce
@@ -0,0 +1,25 @@
+clear
+//Given
+L_ab = 0.4 //mt The total length of the rod
+M = 200 //N_m - the moment acting on rod
+l_1 = 0.1 //mt -moment acting point the distance from 'a'
+R_1 = 100 //N - The Force acting
+l_2 = 0.2 //mt -R_1 acting point the distance from 'a'
+R_2 = 160 //N The Force acting
+l_3 = 0.3 //mt -R_2 acting point the distance from 'a'
+//caliculations
+
+//F_X = 0 forces in x directions
+R_A_X = 0 // since there are no forces in X-direction
+R_B_X = 0
+//M_A = 0 momentum at point a is zero
+
+// M + R_1*l_2 + R_2*l_3 = R_B*L_ab *the moment for a force is FxL
+R_B_Y = (M + R_1*l_2 + R_2*l_3)/L_ab
+
+//M_B= 0 momentum at point b is zero
+// R_A_Y*L_ab + M - R_1*l_2 - R_2*0.1 = 0
+
+R_A_Y = -(M - R_1*l_2 - R_2*0.1)/L_ab
+printf("The X,Y components of reaction force at A is %0.3f,%0.3f N",R_A_X,R_A_Y)
+printf("\n The X,Y components of reaction force at B is %0.3f,%0.3f N",R_B_X,R_B_Y)
diff --git a/3776/CH5/EX5.2/Ex5_2.sce b/3776/CH5/EX5.2/Ex5_2.sce
new file mode 100644
index 000000000..53aac0bc3
--- /dev/null
+++ b/3776/CH5/EX5.2/Ex5_2.sce
@@ -0,0 +1,22 @@
+clear
+//Given
+P_Max = 10 //N - the maximum distribution in a triangular distribution
+L = 3 //mt the total length of force distribution
+L_X = 5 //mt - the horizantal length of the rod
+//caliculations
+
+F_y = P_Max*L*0.5 //N - The force due to triangular distribition
+L_com = 2*L /3 //mt - the resultant force acting as a result of distribution acting position
+//F_X = 0 forces in x directions
+R_A_X = 0 // since there are no forces in X-direction
+R_B_X = 0
+//M_A = 0 momentum at point a is zero
+//F_y*L_com - R_B_Y*L_X = 0
+R_B_Y = F_y*L_com/L_X
+
+//M_B= 0 momentum at point b is zero
+//- R_A_Y*L_X = F_y*(L_X-L )
+
+R_A_Y = - F_y*L/L_X
+printf("The X,Y components of reaction force at A is %0.3f,%0.3f N",R_A_X,R_A_Y)
+printf("\n The X,Y components of reaction force at B is %0.3f,%0.3f N",R_B_X,R_B_Y)
diff --git a/3776/CH5/EX5.3/Ex5_3.sce b/3776/CH5/EX5.3/Ex5_3.sce
new file mode 100644
index 000000000..44cb6144a
--- /dev/null
+++ b/3776/CH5/EX5.3/Ex5_3.sce
@@ -0,0 +1,27 @@
+clear
+//given
+F = 5 //K - force acting on the system
+tan1 = (4/3) // the Tan of the angle of force with x axis
+l_ab = 12 //inch - the total length of ab
+l = 3 // inch - Distance from 'a'
+//caliculation
+F_X = 4 //K
+F_Y = 3 //k
+
+//M_A = 0 momentum at point a is zero
+// F_X*l- R_B_Y*l_ab = 0
+R_B_Y = F_X*l/l_ab
+
+//M_B= 0 momentum at point b is zero
+// R_A_Y*l_ab - F_X*(l_ab - l)
+R_A_Y = F_X*(l_ab - l)/l_ab
+
+//F_X = 0 forces in x directions
+R_A_X = F_Y + R_B_Y
+R_B_X = R_B_Y // since the angle is 45 (180/%pi)*
+
+//resultants
+R_A = (R_A_X**2 + R_A_Y**2**0.5)
+R_B = (R_B_X**2 + R_B_Y**2**0.5)
+printf("The X,Y components and resultant of reaction force at A is %0.3f, %0.3f,%0.3f N",R_A_X,R_A_Y,R_A)
+printf("\nThe X,Y components and resultant of reaction force at B is %0.3f, %0.3f,%0.3f N",R_B_X,R_B_Y,R_B)
diff --git a/3776/CH5/EX5.4/Ex5_4.sce b/3776/CH5/EX5.4/Ex5_4.sce
new file mode 100644
index 000000000..2a3e57db7
--- /dev/null
+++ b/3776/CH5/EX5.4/Ex5_4.sce
@@ -0,0 +1,35 @@
+clear
+//Given
+P_Max = 10 //N - the maximum distribution in a triangular distribution
+L = 3 //mt the total length of force distribution
+L_X = 5 //mt - the horizantal length of the rod
+//caliculations
+
+F_y = P_Max*L*0.5 //N - The force due to triangular distribition
+L_com = 2*L /3 //mt - the resultant force acting as a result of distribution acting position
+//F_X = 0 forces in x directions
+R_A_X = 0 // since there are no forces in X-direction
+R_B_X = 0
+//M_A = 0 momentum at point a is zero
+//F_y*L_com - R_B_Y*L_X = 0
+R_B_Y = F_y*L_com/L_X
+
+//M_B= 0 momentum at point b is zero
+//- R_A_Y*L_X = F_y*(L_X-L )
+
+R_A_Y = - F_y*L/L_X
+
+//For a---a section
+l_a = 2 //mt - a---a section from a
+l_com_a = 2*l_a/3
+v_a = R_A_Y + 0.5*l_a*(10.0*2/3) //*(10*2/3) because the maximum moves
+
+M_a = (10.0*0.66)*l_a*(0.33) + R_A_Y*l_a
+
+//For b---b section
+
+v_b = F_y + R_A_Y //equilabrium conditions
+M_b = (F_y + R_A_Y)*(-1)
+
+printf("\n The force and moment in section a--a are %0.2f kN %0.3f kN-m",v_a,M_a)
+printf("\n The force and moment in section b--b are %0.3f kN %0.3f kN-m",v_b,M_b)
diff --git a/3776/CH5/EX5.9/Ex5_9.sce b/3776/CH5/EX5.9/Ex5_9.sce
new file mode 100644
index 000000000..245adc229
--- /dev/null
+++ b/3776/CH5/EX5.9/Ex5_9.sce
@@ -0,0 +1,30 @@
+clear
+//Given
+P_Max = 10 //N - the maximum distribution in a triangular distribution
+L = 3 //mt the total length of force distribution
+L_X = 5 //mt - the horizantal length of the rod
+//caliculations
+
+F_y = P_Max*L*0.5 //N - The force due to triangular distribition
+L_com = 2*L /3 //mt - the resultant force acting as a result of distribution acting position
+//F_X = 0 forces in x directions
+R_A_X = 0 // since there are no forces in X-direction
+R_B_X = 0
+//M_A = 0 momentum at point a is zero
+//F_y*L_com - R_B_Y*L_X = 0
+R_B_Y = F_y*L_com/L_X
+
+//M_B= 0 momentum at point b is zero
+//- R_A_Y*L_X = F_y*(L_X-L )
+
+R_A_Y = - F_y*L/L_X
+
+//caliculating for some random value
+//For a---a section
+l_a = 2 //mt - a---a section from a
+l_com_a = 2*l_a/3
+v_a = R_A_Y + 0.5*l_a*(10.0*2/3) //*(10*2/3) because the maximum moves
+
+M_a = (10.0*0.66)*l_a*(0.33) + R_A_Y*l_a
+
+printf("\n The force and moment in section a--a are %0.2f KN %0.3f KN-m",v_a,M_a)