diff options
Diffstat (limited to '3776/CH5/EX5.4/Ex5_4.sce')
| -rw-r--r-- | 3776/CH5/EX5.4/Ex5_4.sce | 35 |
1 files changed, 35 insertions, 0 deletions
diff --git a/3776/CH5/EX5.4/Ex5_4.sce b/3776/CH5/EX5.4/Ex5_4.sce new file mode 100644 index 000000000..2a3e57db7 --- /dev/null +++ b/3776/CH5/EX5.4/Ex5_4.sce @@ -0,0 +1,35 @@ +clear +//Given +P_Max = 10 //N - the maximum distribution in a triangular distribution +L = 3 //mt the total length of force distribution +L_X = 5 //mt - the horizantal length of the rod +//caliculations + +F_y = P_Max*L*0.5 //N - The force due to triangular distribition +L_com = 2*L /3 //mt - the resultant force acting as a result of distribution acting position +//F_X = 0 forces in x directions +R_A_X = 0 // since there are no forces in X-direction +R_B_X = 0 +//M_A = 0 momentum at point a is zero +//F_y*L_com - R_B_Y*L_X = 0 +R_B_Y = F_y*L_com/L_X + +//M_B= 0 momentum at point b is zero +//- R_A_Y*L_X = F_y*(L_X-L ) + +R_A_Y = - F_y*L/L_X + +//For a---a section +l_a = 2 //mt - a---a section from a +l_com_a = 2*l_a/3 +v_a = R_A_Y + 0.5*l_a*(10.0*2/3) //*(10*2/3) because the maximum moves + +M_a = (10.0*0.66)*l_a*(0.33) + R_A_Y*l_a + +//For b---b section + +v_b = F_y + R_A_Y //equilabrium conditions +M_b = (F_y + R_A_Y)*(-1) + +printf("\n The force and moment in section a--a are %0.2f kN %0.3f kN-m",v_a,M_a) +printf("\n The force and moment in section b--b are %0.3f kN %0.3f kN-m",v_b,M_b) |