diff options
Diffstat (limited to '3776/CH2')
| -rw-r--r-- | 3776/CH2/EX2.11/Ex2_11.sce | 17 | ||||
| -rw-r--r-- | 3776/CH2/EX2.12/Ex2_12.sce | 7 | ||||
| -rw-r--r-- | 3776/CH2/EX2.19/Ex2_19.sce | 4 | ||||
| -rw-r--r-- | 3776/CH2/EX2.2/Ex2_2.sce | 6 | ||||
| -rw-r--r-- | 3776/CH2/EX2.4/Ex2_4.sce | 14 | ||||
| -rw-r--r-- | 3776/CH2/EX2.6/Ex2_6.sce | 26 | ||||
| -rw-r--r-- | 3776/CH2/EX2.7/Ex2_7.sce | 11 |
7 files changed, 47 insertions, 38 deletions
diff --git a/3776/CH2/EX2.11/Ex2_11.sce b/3776/CH2/EX2.11/Ex2_11.sce index c4e15f631..4f9a017ec 100644 --- a/3776/CH2/EX2.11/Ex2_11.sce +++ b/3776/CH2/EX2.11/Ex2_11.sce @@ -1,21 +1,26 @@ clear -mass = 4 //kg +mass = 4 //kg dist = 1 //mt freely falling distance l = 1500 //mm length of rod d = 15 //mm diameter l_ab = 6.71 //inch l_bc = 8.29 //inch -E = 200 //GPA youngs modulus +E = 200 //GPA youngs modulus k = 4.5 // N/mm stiffness costant F = mass*9.81// The force applying -Area = 3.14*(d**2)/4 -// Two cases -//youngs modulus +Area = 3.14*(d**2)/4 +// Two cases +//youngs modulus e_y = F*l/(Area*E*(10**3)) // stiffness -e_f = F/k +e_f = F/k //total e = e_y +e_f k = 1+(2/(e*(10**-3))) stress_max_1 = F*(1+(k**0.5))/Area printf("\n The maximum stress is: %0.3f MPa",stress_max_1) + +//for the rod without washer +k2 = 1+(2/(e_y*(10**-3))) +stress_max_2 = F*(1+(k2**0.5))/Area +printf("\n The maximum stress for the rod without washer is: %0.3f MPa",stress_max_2) diff --git a/3776/CH2/EX2.12/Ex2_12.sce b/3776/CH2/EX2.12/Ex2_12.sce index b4a566a08..fb8e4ffb6 100644 --- a/3776/CH2/EX2.12/Ex2_12.sce +++ b/3776/CH2/EX2.12/Ex2_12.sce @@ -1,9 +1,10 @@ clear -flex_a = 1//f -flex_b = 2//f +flex_a = 1 //f +flex_b = 2 //f //removing lower support and solving FBD e = -2 -(2+1)//fp //e_1 = (2+1+1)*R //e_1 = -e Making the elongations zero since the both ends are fixed -R = e/(2+1+1.0) //P +R = -e/(2+1+1.0) //P +//since sum of forces are 0 printf("\n The reactions at bottom is %0.3f P",R) diff --git a/3776/CH2/EX2.19/Ex2_19.sce b/3776/CH2/EX2.19/Ex2_19.sce index 2f56f7092..cf1308495 100644 --- a/3776/CH2/EX2.19/Ex2_19.sce +++ b/3776/CH2/EX2.19/Ex2_19.sce @@ -3,8 +3,8 @@ clear l = 30 //in - The length of the rod p_1 = 80 //kips - The Force on the end p_2 = 125 //kips - The force on the other end -A_s = 0.5 //in2 - The crossection of the steel rod -A_a = 0.5 //in2 - The crossection of the aluminium +A_s = 0.5 //sq.in - The crossection of the steel rod +A_a = 0.5 //sq.in - The crossection of the aluminium E_a = 10*(10**6) //psi - The youngs modulus of the aluminium E_s = 30*(10**6) //psi - The youngs modulus of the steel //Internally stastically indeterminant diff --git a/3776/CH2/EX2.2/Ex2_2.sce b/3776/CH2/EX2.2/Ex2_2.sce index 9e6317279..88d9c4ad6 100644 --- a/3776/CH2/EX2.2/Ex2_2.sce +++ b/3776/CH2/EX2.2/Ex2_2.sce @@ -5,9 +5,9 @@ l_cd = 1500 //mm - length of rod cd p_ob = 100 //kN - Force in rods p_bc = -150 //KN p_cd = 50 //KN -A_ob = 1000 //mm2 - Area of rod ob -A_bc = 2000 //mm2 - Area of rod bc -A_cd = 1000 //mm2 - Area of rod cd +A_ob = 1000 //sq.mm - Area of rod ob +A_bc = 2000 //sq.mm - Area of rod bc +A_cd = 1000 //sq.mm - Area of rod cd E = 200.0 //GPA // the total deflection is algebraic sums of `deflection in each module e_1 = p_ob*l_ob/(A_ob*E) diff --git a/3776/CH2/EX2.4/Ex2_4.sce b/3776/CH2/EX2.4/Ex2_4.sce index 76ea23bb6..2a8f3fa43 100644 --- a/3776/CH2/EX2.4/Ex2_4.sce +++ b/3776/CH2/EX2.4/Ex2_4.sce @@ -1,21 +1,23 @@ clear -p_app = 3 //kips - applied force -P_A = 2.23 //kips +p_app = 3 //kips - applied force +P_A = 2.23 //kips p_B = -2.83 //kips - compressive force l_ab = 6.71 //inch l_bc = 8.29 //inch s_ab = 17.8 //ksi - tensile stress s_bc = -12.9 //ksi - compressive stress -E = 10.6 * (10**3) //ksi -youngs modulus +E = 10.6 * (10**3) //ksi -youngs modulus e_ab = s_ab*l_ab/E //elongation e_bc = s_bc*l_bc/E //contraction -x = -e_bc/e_ab //the Ratio of cosines of the deflected angles -// t_1 and t_2 be deflected angles +x = -e_bc/e_ab //the Ratio of cosines of the deflected angles +// t_1 and t_2 be deflected angles //t_2 = 180-45-26.6-t_1 the sum of angles is 360 //applying cos on both sides t_1=atand(1.29) e = e_ab/cosd((t_1)) //inch -k = p_app/e // kips/in vertical stiffness of the combination +e_t = e*cosd(11.2) +k = p_app/e_t // kips/in vertical stiffness of the combination printf("\n The vertical stiffness of the combination is %0.3f kips/inch",k) //answer in textbook is 167 +// answer varies due to rounding off errors diff --git a/3776/CH2/EX2.6/Ex2_6.sce b/3776/CH2/EX2.6/Ex2_6.sce index 844997aec..a5dcb9d0f 100644 --- a/3776/CH2/EX2.6/Ex2_6.sce +++ b/3776/CH2/EX2.6/Ex2_6.sce @@ -1,15 +1,15 @@ clear -dia = 50 //mm - diameter of aluminium -p = 100 // KN - instant force applid -dia_c = 0.1215 //mm- change in diameter +dia = 50 //mm - diameter of aluminium +p = 100 // KN - instant force applied +dia_c = 0.01215 //mm- change in diameter l_c = 0.219 //mm - change in length -l = 300 //mm - length -strain_dia = dia_c/dia // lateral strain -strain_l = l_c/l //longitudinal strain -po = strain_dia/strain_l // poission ratio -area = 3.14*dia*dia/4 //mm2 area -E = p*l/(area*l_c) //N/mm2 youngs modulus -printf("\n The lateral strain is: %0.3f no units",strain_dia) -printf("\n The longitudinal strain is: %0.3f no units",strain_l) -printf("\n The poissions ratio is: %0.3f no units",po) -printf("\n Youngs modulus: %0.2f N/sq.mm",E) +l = 300 //mm - length +strain_dia = -dia_c/dia // lateral strain +strain_l = -l_c/l //longitudinal strain +po = strain_dia/strain_l // Poisson ratio +area = 3.14*dia*dia/4 //sq.mm area +E = p*l/(area*l_c) //N/sq.mm youngs modulus +printf("\n The lateral strain is: %e mm/mm",strain_dia) +printf("\n The longitudinal strain is: %e no units",strain_l) +printf("\n The Poissons ratio is: %0.3f no units",po) +printf("\n Youngs modulus: %0.2f GPa",E) diff --git a/3776/CH2/EX2.7/Ex2_7.sce b/3776/CH2/EX2.7/Ex2_7.sce index c452c6448..0bfdaefa3 100644 --- a/3776/CH2/EX2.7/Ex2_7.sce +++ b/3776/CH2/EX2.7/Ex2_7.sce @@ -1,15 +1,16 @@ clear T = 12.9*(10**-6) ///F -t = 100.00 // F +t = 100.00 // F l_ab = 6.71 //inch l_bc = 8.49 //inch -e_ab = T*t*l_ab //in-elongation +e_ab = T*t*l_ab //in-elongation e_bc = T*t*l_bc //in-elongation -k = e_ab/e_bc // ratio of cosines of deflected angles -// t_1 and t_2 be deflected angles -//t_2 = 180-45-26.6-t_1 the sum of angles is 360 +k = e_ab/e_bc // ratio of cosines of deflected angles +// t_1 and t_2 be deflected angles +//t_2 = 45+26.6-t_1 the sum of angles is 360 //applying cos on both sides t_1 = atand(0.5) // e = e_bc/cosd(t_1) printf("\n The displacement in point B is : %e in",e ) +printf("\n It forms an angle of %f degrees with vertical",45-t_1 ) |