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+// Problem 8.6,Page no.209
+
+clc;clear;
+close;
+
+W=200 //N //weight
+v=4 //m/s //velocity of spring
+sigma=600 //MPa //max allowable stress in spring
+G=80 //GPa //Modulus of rigidity
+rho=78000 //N/m**3 //density
+d=8 //mm //diameter of spring
+D=5 //cm //Mean Diameter of coil
+
+
+//Calculation
+
+E=W*v**2*(2*9.81)**-1 //N*m //Kinetic Energy //Notification has been changed
+
+//U=sigma_s**2*V*(4*G)**-1 //Strain Energy stored inthe spring
+
+//After substituting values in above equation and simplifying we get
+V=163.1*4*80*10**9*((600*10**6)**2)**-1 //Volume
+
+W=rho*V //N //Weight of spring
+
+//Now V=%pi*4**-1*d**2*%pi*D*n
+//After substituting values in above equation and simplifying we get
+n=0.000145*4*(%pi**2*0.008**2*0.05)**-1 //number of turns of spring
+
+//T=P*R=%pi*16**-1*d**3*sigma_s //Torsion
+//After substituting values in above equation and simplifying we get
+P=%pi*0.008**3*600*10**6*(0.025*16)**-1 //N
+
+//Now U=P*dell*2**-1
+//Again,After substituting values in above equation and simplifying we get
+dell=163.1*2*(2412.743)**-1*10**2 //cm
+
+//Result
+printf("The Max Deflection Produced is %.2f",dell);printf(" cm")
+printf("\n Number of coil are %d",ceil(n))