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+// Problem no 7.12,Page no.192
+
+clc;clear;
+close;
+
+P=3680 //KW //Power transmitted
+N=110 //r.p.m 
+X=20000 //N*m //Energy stored
+G=85 //GPa
+
+//Calculations
+
+
+//U*V**-1=X //Strain Energy per unit volume //Notification has been changed
+//X=sigma_s**2*(4*G)**-1*((D**2+d**2)*(D**2)**-1)
+
+T=P*60000*(2*%pi*N)**-1 //N*m //Torque transmitted by shaft
+sigma_s=(20000*3*G*10**9)**(1*2**-1) //MPa //shear stress of shaft
+
+//T=%pi*16**-1*((D**4-d**4)*D**-1)*sigma_s 
+
+//After substituting and simplifying above equations,we get,
+
+d=((T*16*3**0.5)*(%pi*8*sigma_s)**-1)**(1*3**-1)
+D=3**0.5*d 
+
+//Result
+printf("Diameter of shaft is D= %.2f",D);printf(" m")
+printf("\n                      d= %.2f",d);printf(" m")