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+// Problem no 7.11,Page no.191
+
+clc;clear;
+close;
+
+P=4415 //KW //Power transmitted
+N=110 //r.p.m
+sigma_s=75 //MPs //shear stress
+G=85 //GPa
+
+//Calculations
+
+//D=2*d 
+
+T=P*60000*(2*%pi*N)**-1 //N*m //Torque Transmitted
+
+//T=%pi*16**-1*(D**4-d**4)*D**-1*sigma_s //N*m
+
+//After substituting and simplifying above equations,we get,
+
+D=(T*16*%pi**-1*(sigma_s*10**6)**-1)**(1*3**-1)
+d=D*2**-1
+X=5*(sigma_s*10**6)**2*(16*G*10**9)**-1
+
+//U*V**-1 //Energy stored
+//X=U*V**-1 //Energy stored //Notations has been changed
+
+//Result
+printf("Diameter of shaft is:D %.2f",D);printf(" cm")
+printf("\n                     :d %.2f",d);printf(" cm")
+printf("\n Energy stored per cubic meter is %.2f",X);printf(" N/m**2")