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+// Problem no 6.10,Page No.161
+
+clc;clear;
+close;
+
+E=200*10**9 //Pa 
+I=20000*10**-8 //m**4
+
+//Calculations
+
+//Now Taking moment at B
+R_a=(1000*3*4.5+1000*2)*6**-1 //Reaction Force at pt A
+
+//On part BC u.d.l of 1KN/m is introduced both above and below 
+//consider section at distance x i.e X-X and considering moment at section X-X
+
+//M=15500*x*6**-1-1000*x**2*2**-1-1000(x-4)+1000*2**-1*(x-3)**2
+//EI*d**2y*d**x=-M=15500*x*6**-1-1000*x**2*2**-1-1000(x-4)+1000*2**-1*(x-3)**2
+
+//Now Integrating above Equation we get Equation of slope
+//EI*dy*dx**-1=-15500*x**2*12**-1+1000*x**3*6**-1+1000*(x-4)**2*2**-1+1000*6**-1*(x-3)**3+C_1
+
+//Now Integrating above Equation we get Equation of Deflection
+//EI*y=-15500*x**3*36**-1+1000*x**4*24**-1+1000*(x-4)**3*6**-1+1000*24**-1*(x-3)**3+C_1*x+C_2
+
+//At x=0,deflection is zero,i.e y=0  C_2=0
+//At x=6,deflection is zero,i.e y=0  
+x=6
+C_1=-(-15500*x**3*36**-1+1000*x**4*24**-1+1000*(x-4)**3*6**-1+1000*(x-3)**4*24**-1)*x**-1 //Constant
+
+//Answer for constant C_1 is incorrect in Book
+
+//Now Deflection at C,put x=3 m
+x=3
+y_C=1*(E*I)**-1*(-15500*x**3*36**-1+1000*x**4*24**-1+1000*(x-4)**3*6**-1+1000*24**-1*(x-3)**3+C_1*x)*10**3
+
+//Now Deflection at D,put x=4 m
+x=4
+y_D=1*(E*I)**-1*(-15500*x**3*36**-1+1000*x**4*24**-1+1000*(x-4)**3*6**-1+1000*24**-1*(x-3)**3+C_1*x)*10**3
+
+//Answers for y_C & y_D are incorrect in book
+
+//Result
+printf("Deflection at pt C is %.2f mm",y_C)
+printf("\n Deflection at pt D is %.2f mm",y_D)