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+//Example number 8.1, Page number 8.16
+
+
+clc;clear;close
+
+// Variable declaration
+N=6.023*10**26 // unitless
+deltaHv=120 //unitless
+B=1.38*10**-23 //unitless
+k=6.023*10**23//unitless
+
+// Calculations
+n0=0 // 0 in denominator
+n300=N*exp(-deltaHv*10**3/(k*B*300)) // The number of vacancies per kilomole of copper
+n900=N*exp(-(deltaHv*10**3)/(k*B*900)) // The number of vacancies per kilomole of copper
+
+// Results
+printf("at 0K, The number of vacancies per kilomole of copper is : %.f",n0)
+printf("\nat 300K, The number of vacancies per kilomole of copper is : %.3e",(n300))
+printf("\nat 900K, The numbber of vacancies per kilomole of copper is : %.3e",(n900))