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+//Example number 3.8, Page number 3.34
+
+clc;clear;close
+
+// Variable declaration
+d=7300                  // density in (kg/m**3)
+N=6.02*10**26           // Avagadro Number
+A=118.7                 // Atomic Weight
+E=1.9                 // Effective mass
+e=1.6*10**-19
+
+// Calculations
+n=(d*N)/A // no. of electrons
+m=E*9.1*10**-31 // in kg
+x=4*%pi*10**-7*n*e**2 // in kg/m^2
+lamda_L=sqrt(m/x) // in m
+      
+// Result
+printf("Number of electrons per unit volume = %0.1e per m^3",n)
+printf("\nEffective mass of electron ''m*'' = %0.2e kg",m)
+printf("\nPenetration depth = %0.5f Angstroms",(lamda_L*10**8))
+// The answer given in the text book is wrong