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+//Fluid Systems - By - Shiv Kumar
+//Chapter 4 - Pelton Turbine (Impulse Turbine)
+//Example 4.19
+
+ clc
+ clear
+
+//Given Data:-
+ Q=2.5; //Total Discharge, m^3/s
+ Hr=300; //Head from reservoir to base of nozzle, m
+ n=6; //Total number of Jets
+ L=1200; //Lenght of Pipe, m
+ eta_p=92/100; //Efficiency of Power Transmission
+ eta_o=86/100; //Overall Efficiency
+ Cv=0.97; //Co-efficient of Velocity
+ f=0.0025; //Darcy Co-efficient of Friction
+
+
+//Data Used:-
+ rho=1000; //Density of water, kg/m^3
+ g=9.81; //Acceleration due to gravity, m/s^2
+
+//Computations:-
+ h_f=(1-eta_p)*Hr; //m
+ H=Hr-h_f; //Effective Head, m
+ Vi=Cv*sqrt(2*g*H); //Velocity of Jet, m/s
+
+ //(a)Shaft Power, P
+ P=rho*Q*g*H*eta_o/1000; //kW
+
+ //(b)Diameter of the Jet, d
+ q=Q/n; //Discharge per Jet, m^3/s
+ d=sqrt(q/((%pi/4)*Vi)); //m
+
+ //(c)Diameter of the Pipe, D_pipe
+ D_pipe=(64*f*L*Q^2/(h_f*2*g*%pi^2))^(1/5)*1000; //mm
+
+//Results:-
+ printf(" (a)Shaft Power, P=%.3f kW\n",P)
+ printf(" (b)Diameter of the Jet, d=%.4f m\n",d)
+ printf(" (c)Diameter of the Pipe, D_pipe=%.2f mm\n",D_pipe) //The answer vary due to round off error
+
+