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+//Fluid Systems - By - Shiv Kumar
+//Chapter 4 - Pelton Turbine (Impulse Turbine)
+//Example 4.12
+
+ clc
+ clear
+
+//Given Data:-
+ n=2; //Number of Jets
+ P=5000; //Shaft Power, HP
+ N=375; //Speed of Shaft, rpm
+ Hth=200; //Theoretical Head at Base of Nozzle, m
+ eta_p=90/100; //Efficiency of Power Transmission
+ D=1.65; //Diameter of the Runner, m
+ Vel_per=10; //Percentage by which velocity is decreased
+ Deflection=165; //Jet Deflection, degrees
+ eta_o=90/100; //Overall Efficiency
+ Cv=0.98;
+
+
+//Data Used:-
+ rho=1000; //Density of water, kg/m^3
+ g=9.81; //Acceleration due to gravity, m/s^2
+
+//Computations:-
+ P=P*736; //W
+ Hact=eta_p*Hth; //Actual Head available at base of Nozzle, m
+ Vro_by_Vri=1-Vel_per/100; //Vro/Vri
+ beta_o=180-Deflection; //degrees
+
+ u=%pi*D*N/60; //Velocity of Runner, m/s
+ ui=u;
+ uo=u;
+ Vi=Cv*sqrt(2*g*Hact); //m/s
+ Vwi=Vi;
+ Vri=Vi-u; //m/s
+ Vro=Vri*Vro_by_Vri; //m/s
+ Vrwo=Vro*cosd(beta_o); //m/s
+ Vwo=uo-Vrwo; //m/s
+
+ //(a)Efficiency of Runner, eta_H
+ eta_H=2*(Vwi-Vwo)*u/Vi^2*100; //In Perecentage
+
+ //(b)Diameter of each jet, d
+ Q=P/(rho*g*Hact*eta_o); //Discharge, m^3/s
+ d=sqrt(Q/((%pi/4)*n*Vi)); //Diameter of each Jet, m
+
+//Results:-
+ printf("(a)Efficiency of the Runner, eta_H=%.2f Percent\n",eta_H) //The answer vary due to round off error
+ printf("(b)Diameter of each Jet , d=%.3f m\n",d)
+