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+// Ex 47 Page 391
+
+clc;clear;close;
+// Given
+V=500;//V
+ns=60;//slots
+nc=20;//conductor/slot
+ra=1.31;//ohm
+Tmax=218;//N-m
+fi=23*10**-3;//Wb
+
+Tmin=Tmax/1.5//N-m
+Z=ns*nc;//no of conductors
+Ia=Tmax/(.159*fi*Z);//A
+Imax=1.5*Ia;//A
+I1=Imax;//A
+I2=Ia;//A
+R1=V/I1;//ohm
+n= log(R1/ra)/log(I1/I2)+1;//no of studs
+N=n-1;//no of section
+printf("no of studs = %d and no. of section = %d",n,N)
+R2=R1*(I2/I1);//ohm
+R3=R2*(I2/I1);//ohm
+R4=R3*(I2/I1);//ohm
+R1s=R1-R2;//ohm
+R2s=R2-R3;//ohm
+R3s=R3-R4;//ohm
+R4s=R4-ra;//ohm
+printf("\n\n Resistance of 1st section = %.2f ohm",R1s)
+printf("\n Resistance of 2nd section = %.2f ohm",R2s)
+printf("\n Resistance of 3rd section = %.2f ohm",R3s)
+printf("\n Resistance of 4th section = %.2f ohm",R4s)