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+// Ex 20 Page 361
+
+clc;clear;close;
+// Given
+//Ia=0.0004*(Va+40*Vg)**(3/2);// mA --eqn(1)
+Va=250;//V
+Vg=-3;//V
+//mu=delVa/delVg
+//differentiation wrt Vg eqn(1)
+//(4*10**-6*3/2*(Va+40*Vg))**(1/2)*(mu+40)=0
+mu=-40;//constant
+printf("Amplification factor, mu = %.f",mu)
+//differentiation wrt Va eqn(1)
+//delIa/delVa=(4*10**-6*3/2*(Va+40*Vg))**(1/2)*(0+40)
+gm=(4*10**-6*3/2)*(Va+40*Vg)**(1/2)*(0+40)*1000;// mA/V or S
+printf("\n Mutual conductance, gm = %.2f S",gm)
+//differentiation wrt Ia eqn(1) keeping Vg constant
+//1=(4*10**-6)*3/2*(Va+40*Vg)**(1/2)*(delVa/delIa+0)
+//ra=delVa/delIa
+ra=1/((4*10**-6)*3/2*(Va+40*Vg)**(1/2))
+printf("\n Plate resistance, ra = %.1f kohm",ra/1000)