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+// Example 34_32
+clc;funcprot(0);
+//Given data
+P=200;// MW
+Fc=24*10^6;// Fixed cost Rs./year
+Cf=1800;// Cost of fuel in Rs./ton
+CV=20000;// Calorific value in kJ/kg
+Oe=280;// Other expanses in Rs./kW
+Q_1=18000;// Plant heat rate at 100% capacity factor in kJ/kWh
+F_c1=100/100;// Capacity factor
+Q_2=10500;// Plant heat rate at 50% capacity factor in kJ/kWh
+F_c2=50/100;// Capacity factor
+
+//Calculation
+Fc=Oe+(Fc/(P*10^3));// Fixed cost per kW capacity  per year in Rs./kW
+
+//(a)At 100% C.F
+AD=P*10^3*F_c1;// The average demand in kW
+E_g=AD*8760;// Energy generated per year in kWh
+Fc_1=((Fc*AD)/(E_g))*100;// Fixed cost per kWh in paise
+C=Q_1/CV;// Coal burned per kWh in kg
+Cc=(C*Cf)/1000;// Cost of coal per kWh energy generated in rupees
+Tc_1=(Fc_1/100)+Cc;// Total cost of generation per kWh in rupees
+
+//(b)At 50% C.F
+AD=P*10^3*F_c2;// The average demand in kW
+E_g=AD*8760;// Energy generated per year in kWh
+Fc_2=((Fc*AD)/(E_g))*100;// Fixed cost per kWh in paise
+C=Q_2/CV;// Coal burned per kWh in kg
+Cc=(C*Cf)/1000;// Cost of coal per kWh energy generated in rupees
+Tc_2=(Fc_2/100)+Cc;// Total cost of generation per kWh in rupees
+printf('\n(a)Total cost of generation per kWh=Rs.%0.3f \n(b)Total cost of generation per kWh=Rs.%0.3f',Tc_1,Tc_2);
+// The answer provided in the textbook is wrong