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+// Example 34_20
+clc;funcprot(0);
+//Given data
+P=120;// Plant capacity in MW
+CC=15000;// The Capital cost in Rs/kW
+Arc=20*10^6;// Annual running charges in rupees
+F_al=0.6;// The annual load factor
+F_ac=0.5;// Annual capacity factor
+
+//Calculation
+MD=(P*F_ac)/F_al;// Maximum demand in MW
+Rc=P-MD;// Reserve capacity in MW
+L_a=F_al*MD;// Average load in MW
+E_py=L_a*10^3*8760;//Energy produced/year in kWh
+E_a=E_py*0.95;// kWh
+TCC=CC*P*10^3;// Total capital cost of the plant in rupees
+ID=.10*TCC;// Interest and decpreciation in rupees
+p=.10*TCC;// Profit to be gained in rupees
+TC=ID+p+Arc;// Total charges to be recovered in rupees
+C_eg=(TC/E_a);// Cost of energy generated in Rs./kWh
+printf('\n(a)The reserve capacity=%0.0f MW \n(b)Cost of energy generated=Rs.%0.2f/kWh',Rc,C_eg);