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+//Chapter 15: Environmental Pollution and Control
+//Problem: 1
+clc;
+
+MM = 294// Molar mass, K2Cr2O7
+
+//Declaration of Variables
+v_eff = 25   // cm cube, 
+v = 8.3      // cm cube, K2Cr2O7
+M = 0.001    // M, K2Cr2O7
+
+// Solution
+w = v * 8 * 6 * M / 1000.
+
+mprintf("8.3 cm cube of 0.006 N K2Cr2O7 =%.2e g of O2\n",w)
+mprintf(" 25 ml of the effluent requires %.2e g of O2\n",w)
+
+cod = w * 10 ** 6 / 25.
+mprintf(" 1l of the effluent requires %.2fg of O2\n",cod)
+mprintf(" COD of the effluent sample is %.2f ppm or mg/L",cod)