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//Chapter 15: Environmental Pollution and Control
//Problem: 1
clc;
MM = 294// Molar mass, K2Cr2O7
//Declaration of Variables
v_eff = 25 // cm cube,
v = 8.3 // cm cube, K2Cr2O7
M = 0.001 // M, K2Cr2O7
// Solution
w = v * 8 * 6 * M / 1000.
mprintf("8.3 cm cube of 0.006 N K2Cr2O7 =%.2e g of O2\n",w)
mprintf(" 25 ml of the effluent requires %.2e g of O2\n",w)
cod = w * 10 ** 6 / 25.
mprintf(" 1l of the effluent requires %.2fg of O2\n",cod)
mprintf(" COD of the effluent sample is %.2f ppm or mg/L",cod)
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