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+//Example 2_15 page no:81
+clc
+//applying kirchoff law to node 1
+R5=5//resistance in ohm
+V=10//source voltge
+resistance=[0.83,-0.5,0;-0.5,1.5,0.7;0.01,1,-1]
+current=[10,2,20]
+volt=inv(resistance)'*current'//calculating V1 V2 V3
+I3=(volt(3,1)-8.8)/R5
+disp(I3,"current flowing through 5 ohm resistor is (in ampere)")
+disp("negative sign indicate flow of current in opposite direction")