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+//Example 1_5 page no:23
+clc;
+//applying kirchoff law
+V=-20*10^-3/(-4.25*10^-3);
+P3=66.55;
+P20=-20*V;
+P4=V*V/(4);
+P=V*V/1;
+disp(P3,"the power absorbed by 3i current source is (in mW)");
+disp(P20,"the power absorbed by 20mA current source is (in mW)");
+disp(P4,"the power absorbed by 4 kilo ohm current source is (in mW)");
+disp(P,"the power absorbed by 1 kilo ohm current source is (in mW)");
+//in text book V value is rounded off but here the value is not rounded and used directly
+//so power result varies slightly
+//in text book V is rounded to 4.71 V