diff options
Diffstat (limited to '3655/CH4/EX4.9/Ex4_9.sce')
-rw-r--r-- | 3655/CH4/EX4.9/Ex4_9.sce | 79 |
1 files changed, 79 insertions, 0 deletions
diff --git a/3655/CH4/EX4.9/Ex4_9.sce b/3655/CH4/EX4.9/Ex4_9.sce new file mode 100644 index 000000000..c2515340a --- /dev/null +++ b/3655/CH4/EX4.9/Ex4_9.sce @@ -0,0 +1,79 @@ +// Example 4.9 +// Computation for the magnitude and polarity of the Hall voltage between the terminal 1 & 2,the value of Hall coefficient for case(A) and case(B),Hall coefficient and mobility of the majority carrier of the semiconductor for case(D)// +// Page no.108 + +clc; +clear; +close; + +//Given data ; +e=1.60*10^-19; +nn=2.5*10^15; +B=6*10^-5; +I=10*10^-3; +w=5*10^-1 +p1=4.0*10^-4; +Pp=2.5*10^15; +VH3=6*10^-3; +w3=0.5; +d=0.4; +Vd=5; +l=1.2; + + +//...................................(A)....................................// + +//Calculation for charge density p// +p=-e*nn; + +//negative sign denotes the tyoe of majority carrier in the conduction of current in the semiconductor is eletron// + +//Calculation for magnitude of the Hall voltage// +VH=(B*I)/(p1*w); + +//the polarity of Hall voltage at terminal1 is negative with respect to the terminal2// + +//Calculation for Hall coefficient// +RH=1/p; + +//...................................(B)....................................// + +//Calculation for the charge density// +p2=e*Pp; + +//Calculation for magnitude of the Hall voltage// +VH2=(B*I)/(p2*w); + +//Calculation for Hall coefficient// +RH2=1/p2; + +//The holes are deflected in the -Y direction as electron and hence the terminal1 will be positive with respect to the termninal2// + +//...................................(D)....................................// + +//Calculation for Hall coefficient// +RH3=(VH3*w3)/(I*B); + +//Calculation for concentration of holes in semiconductor// +Pp3=1/(e*RH3); + +//Calculation for mobility of the holes// +mu_p=(l/d)*(VH3/(B*Vd)); + + +//Displaying the result in command window +printf("........................Part (A).........................."); +printf('\n \n Charge density = %0.1f x 10^-4 C/cm3',p*10^4); +printf('\n \n Magnitude of the Hall voltage = %0.1f x 10^-3 V',VH*10^3); +printf('\n \n Hall coefficient = %0.1f x 10^3 cm3/C',RH*10^-3); +printf("\n \n ........................Part (B).........................."); +printf('\n \n Charge density = %0.1f x 10^-4 C/cm3',p2*10^4); +printf('\n \n Magnitude of the Hall voltage = %0.0f mV',VH2*10^3); +printf('\n \n Hall coefficient = %0.1f x 10^3 cm3/C',RH2*10^-3); +printf("\n \n ........................Part (D).........................."); +printf('\n \n Hall coefficient = %0.0f x 10^3 cm3/C',RH3*10^-3); +printf('\n \n Concentration of holes in semiconductor = %0.2f x 10^15 cm^-3',Pp3*10^-15); +printf('\n \n Mobility of the holes = %0.0f cm2/V sec',mu_p); + + +//Answers are varying due to round off error// |