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-rw-r--r--3648/CH10/EX10.1/Ex10_1.sce13
-rw-r--r--3648/CH10/EX10.1/Ex10_1.txt1
-rw-r--r--3648/CH10/EX10.10/Ex10_10.sce13
-rw-r--r--3648/CH10/EX10.10/Ex10_10.txt1
-rw-r--r--3648/CH10/EX10.2/Ex10_2.sce10
-rw-r--r--3648/CH10/EX10.2/Ex10_2.txt3
-rw-r--r--3648/CH10/EX10.3/Ex10_3.sce14
-rw-r--r--3648/CH10/EX10.3/Ex10_3.txt3
-rw-r--r--3648/CH10/EX10.4/Ex10_4.sce10
-rw-r--r--3648/CH10/EX10.4/Ex10_4.txt1
-rw-r--r--3648/CH10/EX10.5/Ex10_5.sce12
-rw-r--r--3648/CH10/EX10.5/Ex10_5.txt1
-rw-r--r--3648/CH10/EX10.6/Ex10_6.sce13
-rw-r--r--3648/CH10/EX10.6/Ex10_6.txt3
-rw-r--r--3648/CH10/EX10.7/Ex10_7.sce9
-rw-r--r--3648/CH10/EX10.7/Ex10_7.txt1
-rw-r--r--3648/CH10/EX10.8/Ex10_8.sce17
-rw-r--r--3648/CH10/EX10.8/Ex10_8.txt1
-rw-r--r--3648/CH10/EX10.9/Ex10_9.sce12
-rw-r--r--3648/CH10/EX10.9/Ex10_9.txt1
20 files changed, 139 insertions, 0 deletions
diff --git a/3648/CH10/EX10.1/Ex10_1.sce b/3648/CH10/EX10.1/Ex10_1.sce
new file mode 100644
index 000000000..81086d522
--- /dev/null
+++ b/3648/CH10/EX10.1/Ex10_1.sce
@@ -0,0 +1,13 @@
+ //Example 10_1
+clc();
+clear;
+//To find out the pressure in Lungs
+h=6 //units in cm Hg
+Pa=76 //Units in cm Hg
+Pl=(h+Pa) //units in cm Hg
+
+Pl=Pl*10^-2 //units in Meters Hg
+g=9.8 //Units in Meters/cm^2
+H=13600 //Constant
+Pl=Pl*H*g //Units in Pa
+printf("The pressure in the lungs is Pl=%.1f Pa",Pl)
diff --git a/3648/CH10/EX10.1/Ex10_1.txt b/3648/CH10/EX10.1/Ex10_1.txt
new file mode 100644
index 000000000..66fa22528
--- /dev/null
+++ b/3648/CH10/EX10.1/Ex10_1.txt
@@ -0,0 +1 @@
+The pressure in the lungs is Pl=109289.6 Pa \ No newline at end of file
diff --git a/3648/CH10/EX10.10/Ex10_10.sce b/3648/CH10/EX10.10/Ex10_10.sce
new file mode 100644
index 000000000..c3fb63c87
--- /dev/null
+++ b/3648/CH10/EX10.10/Ex10_10.sce
@@ -0,0 +1,13 @@
+//Example 10_10
+clc();
+clear;
+//To findout how fast the nitrogen molecule moving in air
+M=28 //Units in Kg/Mol
+Na=6.02*10^26 //Units in K mol^-1
+mo=M/Na //Units in Kg
+k=1.38*10^-23 //units in J/K
+T=27+273 //Units in K
+v2=(3*k*T)/mo //unit in Meter^2/Sec^2
+v=sqrt(v2) //Units in meter/sec
+printf("The nitrogen molecule goes at a speed of V=%d meter/sec",v)
+//In text book the answer is printed wrong as v=517 m/sec the correct answer is v=516 meter/ sec
diff --git a/3648/CH10/EX10.10/Ex10_10.txt b/3648/CH10/EX10.10/Ex10_10.txt
new file mode 100644
index 000000000..a20a8465e
--- /dev/null
+++ b/3648/CH10/EX10.10/Ex10_10.txt
@@ -0,0 +1 @@
+The Final pressure is P2=328 K Pa \ No newline at end of file
diff --git a/3648/CH10/EX10.2/Ex10_2.sce b/3648/CH10/EX10.2/Ex10_2.sce
new file mode 100644
index 000000000..b7615947c
--- /dev/null
+++ b/3648/CH10/EX10.2/Ex10_2.sce
@@ -0,0 +1,10 @@
+//Example 10_2
+clc();
+clear;
+//To find the mass of copper atom
+maa=63.5 //Units in Kgs
+n=6.022*10^26 //Units in number of atoms
+Mass=maa/n //units in Kg/atom
+printf("The Mass per atom is=")
+disp(Mass)
+printf("Kg/Atom")
diff --git a/3648/CH10/EX10.2/Ex10_2.txt b/3648/CH10/EX10.2/Ex10_2.txt
new file mode 100644
index 000000000..c0a73e04f
--- /dev/null
+++ b/3648/CH10/EX10.2/Ex10_2.txt
@@ -0,0 +1,3 @@
+The Mass per atom is=
+ 1.054D-25
+Kg/Atom \ No newline at end of file
diff --git a/3648/CH10/EX10.3/Ex10_3.sce b/3648/CH10/EX10.3/Ex10_3.sce
new file mode 100644
index 000000000..9f0e22d76
--- /dev/null
+++ b/3648/CH10/EX10.3/Ex10_3.sce
@@ -0,0 +1,14 @@
+
+//Example 10_3
+clc();
+clear;
+//To find te volume associated with mercury atom in liquid mercury
+M=201 //Units in Kg/Kmol
+n=6.02*10^26 //units in K mol^-2
+mo=M/n //units in Kg
+n1=13600 //units in Kg/Meter^3
+noatoms=n1/mo //units in atoms/Meter^3
+volume_atom=1/noatoms //units in Meter^3/Atom
+printf("The volume associated is ")
+disp(volume_atom)
+printf("Meter^3/Atom")
diff --git a/3648/CH10/EX10.3/Ex10_3.txt b/3648/CH10/EX10.3/Ex10_3.txt
new file mode 100644
index 000000000..1e79fcc3a
--- /dev/null
+++ b/3648/CH10/EX10.3/Ex10_3.txt
@@ -0,0 +1,3 @@
+The volume associated is
+ 2.455D-29
+Meter^3/Atom \ No newline at end of file
diff --git a/3648/CH10/EX10.4/Ex10_4.sce b/3648/CH10/EX10.4/Ex10_4.sce
new file mode 100644
index 000000000..b76717aa5
--- /dev/null
+++ b/3648/CH10/EX10.4/Ex10_4.sce
@@ -0,0 +1,10 @@
+//Example 10_4
+clc();
+clear;
+//To find the volume that one kilomole of an ideal gas occupies
+p=1.013*10^5 //units in Pa
+t=273.15 //units in K
+n=1 //units in K mol
+R=8314 //units in J/Kmol K
+v=(n*R*t)/p //units in Meter^3/Kmol
+printf("Volume occupied is V=%.1f Meter^3/Kmol",v)
diff --git a/3648/CH10/EX10.4/Ex10_4.txt b/3648/CH10/EX10.4/Ex10_4.txt
new file mode 100644
index 000000000..88e66bc57
--- /dev/null
+++ b/3648/CH10/EX10.4/Ex10_4.txt
@@ -0,0 +1 @@
+Volume occupied is V=22.4 Meter^3/Kmol \ No newline at end of file
diff --git a/3648/CH10/EX10.5/Ex10_5.sce b/3648/CH10/EX10.5/Ex10_5.sce
new file mode 100644
index 000000000..b3b6e760b
--- /dev/null
+++ b/3648/CH10/EX10.5/Ex10_5.sce
@@ -0,0 +1,12 @@
+//Example 10_5
+clc();
+clear;
+//To find the gas pressure in the container
+v=5*10^-3 //units in meter^3
+t=300 //units in K
+m1=14*10^-6 //Units in Kg
+M=28 //Units in Kg/Kmol
+n=m1/M //units in K mol
+R=8314 //units in J/Kmol K
+p=(n*R*t)/v //units in Meter^3/Kmol
+printf("The pressure in the container is P=%d Pa",p)
diff --git a/3648/CH10/EX10.5/Ex10_5.txt b/3648/CH10/EX10.5/Ex10_5.txt
new file mode 100644
index 000000000..f884ff1aa
--- /dev/null
+++ b/3648/CH10/EX10.5/Ex10_5.txt
@@ -0,0 +1 @@
+ The pressure in the container is P=249 Pa \ No newline at end of file
diff --git a/3648/CH10/EX10.6/Ex10_6.sce b/3648/CH10/EX10.6/Ex10_6.sce
new file mode 100644
index 000000000..a8aced99f
--- /dev/null
+++ b/3648/CH10/EX10.6/Ex10_6.sce
@@ -0,0 +1,13 @@
+//Example 10_6
+clc();
+clear;
+//To determine the mass of the air in flask
+p=1.013*10^5 //Units in Pa
+v=50*10^-6 //Units in meter^3
+M=28 //Units in Kg/Mol
+R=8314 //units in J/Kmol K
+T=293 //units in K
+m=(p*v*M)/(R*T) //Units in Kg
+printf("The mass of air in flask is=")
+disp(m)
+printf("Kg")
diff --git a/3648/CH10/EX10.6/Ex10_6.txt b/3648/CH10/EX10.6/Ex10_6.txt
new file mode 100644
index 000000000..3439c0566
--- /dev/null
+++ b/3648/CH10/EX10.6/Ex10_6.txt
@@ -0,0 +1,3 @@
+The mass of air in flask is=
+ 0.0000582
+Kg \ No newline at end of file
diff --git a/3648/CH10/EX10.7/Ex10_7.sce b/3648/CH10/EX10.7/Ex10_7.sce
new file mode 100644
index 000000000..b65aac605
--- /dev/null
+++ b/3648/CH10/EX10.7/Ex10_7.sce
@@ -0,0 +1,9 @@
+//Example 10_7
+clc();
+clear;
+//To find out the final pressure in the drum
+p1=1 //Units in atm
+t2=333 //units in K
+t1=293 //units in K
+p2=p1*(t2/t1) //units in atm
+printf("The final pressure in the drum is P2=%.2f atm",p2)
diff --git a/3648/CH10/EX10.7/Ex10_7.txt b/3648/CH10/EX10.7/Ex10_7.txt
new file mode 100644
index 000000000..c7bfbb695
--- /dev/null
+++ b/3648/CH10/EX10.7/Ex10_7.txt
@@ -0,0 +1 @@
+The final pressure in the drum is P2=1.14 atm \ No newline at end of file
diff --git a/3648/CH10/EX10.8/Ex10_8.sce b/3648/CH10/EX10.8/Ex10_8.sce
new file mode 100644
index 000000000..928c3448f
--- /dev/null
+++ b/3648/CH10/EX10.8/Ex10_8.sce
@@ -0,0 +1,17 @@
+//Example 10_8
+clc();
+clear;
+//To find the final volume of gas
+
+t1=27 //Units in Centigrade
+t1=t1+273 //Units in Kelvin
+t2=547 //Units in Centigrade
+t2=t2+273 //Units in Kelvin
+t1=27 //Units in Centigrade
+t1=t1+273 //Units in Kelvin
+t1=27 //Units in Centigrade
+t1=t1+273 //Units in Kelvin
+p2=3700 //units in cm Hg
+p1=74 //units in cm Hg
+v1_v2=1/((t1/t2)*(p2/p1)) //In terms of V1
+printf("The final volume of gas in terms of original volume is V2=%.5f*V1",v1_v2)
diff --git a/3648/CH10/EX10.8/Ex10_8.txt b/3648/CH10/EX10.8/Ex10_8.txt
new file mode 100644
index 000000000..a50ec07f0
--- /dev/null
+++ b/3648/CH10/EX10.8/Ex10_8.txt
@@ -0,0 +1 @@
+The final volume of gas in terms of original volume is V2=0.05467*V1 \ No newline at end of file
diff --git a/3648/CH10/EX10.9/Ex10_9.sce b/3648/CH10/EX10.9/Ex10_9.sce
new file mode 100644
index 000000000..9f841aec9
--- /dev/null
+++ b/3648/CH10/EX10.9/Ex10_9.sce
@@ -0,0 +1,12 @@
+//Example 10_9
+clc();
+clear;
+//To find the pressure after the car has been driven at high speed
+t2=308 //Units in K
+t1=273 //Units in K
+p2_p1=(t2)/t1 //In terms of P1
+P1=190 //Units in K Pa
+P2=101 //Units in K Pa
+P2=p2_p1*(P1+P2) //Units in K Pa
+printf("The Final pressure is P2=%d K Pa",round(P2))
+//In text book the answer is printed wrong as P2=329 K Pa but the correct answer is 328 K Pa
diff --git a/3648/CH10/EX10.9/Ex10_9.txt b/3648/CH10/EX10.9/Ex10_9.txt
new file mode 100644
index 000000000..a20a8465e
--- /dev/null
+++ b/3648/CH10/EX10.9/Ex10_9.txt
@@ -0,0 +1 @@
+The Final pressure is P2=328 K Pa \ No newline at end of file