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//Example 10_3
clc();
clear;
//To find te volume associated with mercury atom in liquid mercury
M=201 //Units in Kg/Kmol
n=6.02*10^26 //units in K mol^-2
mo=M/n //units in Kg
n1=13600 //units in Kg/Meter^3
noatoms=n1/mo //units in atoms/Meter^3
volume_atom=1/noatoms //units in Meter^3/Atom
printf("The volume associated is ")
disp(volume_atom)
printf("Meter^3/Atom")
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