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-rw-r--r--3556/CH4/EX4.1/Ex4_1.sce33
-rw-r--r--3556/CH4/EX4.13/Ex4_13.sce38
-rw-r--r--3556/CH4/EX4.16/Ex4_16.sce42
-rw-r--r--3556/CH4/EX4.17/Ex4_17.sce25
-rw-r--r--3556/CH4/EX4.18/Ex4_18.sce39
-rw-r--r--3556/CH4/EX4.3/Ex4_3.sce34
-rw-r--r--3556/CH4/EX4.6/Ex4_6.sce36
-rw-r--r--3556/CH4/EX4.8/Ex4_8.sce46
8 files changed, 293 insertions, 0 deletions
diff --git a/3556/CH4/EX4.1/Ex4_1.sce b/3556/CH4/EX4.1/Ex4_1.sce
new file mode 100644
index 000000000..8df2bb037
--- /dev/null
+++ b/3556/CH4/EX4.1/Ex4_1.sce
@@ -0,0 +1,33 @@
+clc
+// Fundamental of Electric Circuit
+// Charles K. Alexander and Matthew N.O Sadiku
+// Mc Graw Hill of New York
+// 5th Edition
+
+// Part 1 : DC Circuits
+// Chapter 4 : Circuit Theorems
+// Example 4 - 1
+
+clear; clc; close;
+//
+// Given data
+R = 76.00000
+Vs1 = 12.0000;
+Vs2 = 24.0000;
+//
+// Calculations Io for Vs = 12.0000
+I21 = Vs1/R;
+Io_1 = I21;
+// Calculations Io for Vs = 24.0000
+I22 = Vs2/R;
+Io_2 = I22;
+//
+// Display the result
+disp("Example 4-1 Solution : ");
+printf(" \n Io_1 = Current Io For Vs 12 Volt = %.3f A",Io_1)
+printf(" \n Io_2 = Current Io For Vs 24 Volt = %.3f A",Io_2)
+
+
+
+
+
diff --git a/3556/CH4/EX4.13/Ex4_13.sce b/3556/CH4/EX4.13/Ex4_13.sce
new file mode 100644
index 000000000..f2925dfe0
--- /dev/null
+++ b/3556/CH4/EX4.13/Ex4_13.sce
@@ -0,0 +1,38 @@
+clc
+// Fundamental of Electric Circuit
+// Charles K. Alexander and Matthew N.O Sadiku
+// Mc Graw Hill of New York
+// 5th Edition
+
+// Part 1 : DC Circuits
+// Chapter 4 : Circuit Theorems
+// Example 4 - 13
+
+clear; clc; close;
+//
+// Given data
+R2 = 2.00;
+R3 = 3.00;
+R6 = 6.00;
+R12 = 12.00;
+Vth = 22.00;
+//
+// Calculations
+// Series R2 and R3
+Rs1 = R2 + R3;
+// Parallel R6 and R12
+Rp1 = (R6*R12)/(R6 + R12);
+// Resistance Total
+Rt = Rs1 + Rp1;
+// Calculations Maximum Power
+Pmax = (Vth^2)/(4*Rt);
+//
+// Display the result
+disp("Example 4-13 Solution : ");
+printf(" \n Rth = Rl = %.3f Ohm",Rt)
+printf(" \n Pmax = Maximum Power = %.3f Watt",Pmax)
+
+
+
+
+
diff --git a/3556/CH4/EX4.16/Ex4_16.sce b/3556/CH4/EX4.16/Ex4_16.sce
new file mode 100644
index 000000000..3f3970ca9
--- /dev/null
+++ b/3556/CH4/EX4.16/Ex4_16.sce
@@ -0,0 +1,42 @@
+clc
+// Fundamental of Electric Circuit
+// Charles K. Alexander and Matthew N.O Sadiku
+// Mc Graw Hill of New York
+// 5th Edition
+
+// Part 1 : DC Circuits
+// Chapter 4 : Circuit Theorems
+// Example 4 - 16
+
+clear; clc; close;
+//
+// Given data
+Voc = 12.4000;
+VL = 12.0000;
+PL = 2.0000;
+RL1 = 8.0000;
+// Part a
+// Calculations Vs
+Vs = Voc;
+// Calculations RL
+RL = (VL)^2/(PL);
+// Calculations IL
+IL = VL/RL;
+// Calculation Internal Resistance
+Rs = (Voc - VL)/IL;;
+//
+// Part b
+// Calculations V
+V8 = (RL1/(Rs + RL1))*Vs;
+//
+// Display the result
+disp("Example 4-16 Solution : ");
+printf(" Part a")
+printf(" \n Vs = Source Voltage = %.3f Volt",Vs)
+printf(" \n Rs = Resistance Internal = %.3f Ohm",Rs)
+printf(" \n Part b")
+printf(" \n V8 = Load Voltage With 8 Ohm = %.3f Volt",V8)
+
+
+
+
diff --git a/3556/CH4/EX4.17/Ex4_17.sce b/3556/CH4/EX4.17/Ex4_17.sce
new file mode 100644
index 000000000..72dff20cd
--- /dev/null
+++ b/3556/CH4/EX4.17/Ex4_17.sce
@@ -0,0 +1,25 @@
+clc
+// Fundamental of Electric Circuit
+// Charles K. Alexander and Matthew N.O Sadiku
+// Mc Graw Hill of New York
+// 5th Edition
+
+// Part 1 : DC Circuits
+// Chapter 4 : Circuit Theorems
+// Example 4 - 17
+
+clear; clc; close;
+// Given data
+R1 = 500.0000;
+R2 = 125.0000;
+R3 = 200.0000;
+//
+// Calculations Rx
+Rx = (R3/R1)*R2; // Rx = Resistance x
+//
+// Display the result
+disp("Example 4-17 Solution : ");
+printf(" \n Rx = Resistance X = %.3f Ohm",Rx)
+
+
+
diff --git a/3556/CH4/EX4.18/Ex4_18.sce b/3556/CH4/EX4.18/Ex4_18.sce
new file mode 100644
index 000000000..2142dd443
--- /dev/null
+++ b/3556/CH4/EX4.18/Ex4_18.sce
@@ -0,0 +1,39 @@
+clc
+// Fundamental of Electric Circuit
+// Charles K. Alexander and Matthew N.O Sadiku
+// Mc Graw Hill of New York
+// 5th Edition
+
+// Part 1 : DC Circuits
+// Chapter 4 : Circuit Theorems
+// Example 4 - 18
+
+clear; clc; close;
+//
+// Given data
+Vs = 220.0000;
+R1 = 1000.0000;
+R3 = 3000.0000;
+R4 = 400.0000;
+R6 = 600.0000;
+Rm = 40.0000;
+//
+// Calculations Rp1
+Rp1 = (R1*R3)/(R1 + R3);
+// Calculations Rp2
+Rp2 = (R4*R6)/(R4 + R6);
+// Calculations Rs1
+Rth = Rp1 + Rp2
+// Calculation Vth
+V1 = (R1/(R1 + R3))*Vs;
+V2 = (R6/(R4+R6))*Vs;
+Vth = V1 - V2;
+// Calculation IG
+IG = Vth/(Rth + Rm)
+//
+// Display the result
+disp("Example 4-18 Solution : ");
+printf(" \n IG = Current Through The Galvanometer = %.3f mA",IG*1000)
+
+
+
diff --git a/3556/CH4/EX4.3/Ex4_3.sce b/3556/CH4/EX4.3/Ex4_3.sce
new file mode 100644
index 000000000..405bbd380
--- /dev/null
+++ b/3556/CH4/EX4.3/Ex4_3.sce
@@ -0,0 +1,34 @@
+clc
+// Fundamental of Electric Circuit
+// Charles K. Alexander and Matthew N.O Sadiku
+// Mc Graw Hill of New York
+// 5th Edition
+
+// Part 1 : DC Circuits
+// Chapter 4 : Circuit Theorems
+// Example 4 - 3
+
+clear; clc; close;
+//
+// Given data
+R1 = 8.00000
+R2 = 4.0000;
+Vs = 6.0000;
+Is = 3.0000;
+//
+// Calculations V4 for Vs = 6 Volt
+I1 = Vs/(R1+R2);
+V1 = R2*I1;
+// Calculations V4 for Is = 3 Ampere
+I3 = (R1/(R1+R2))*Is;
+V2 = R2*I3;
+// Calcucations Total V4
+V4 = V1 + V2;
+// Display the result
+disp("Example 4-3 Solution : ");
+printf(" \n V4 = Voltage For R 4 ohm = %.3f Volt",V4)
+
+
+
+
+
diff --git a/3556/CH4/EX4.6/Ex4_6.sce b/3556/CH4/EX4.6/Ex4_6.sce
new file mode 100644
index 000000000..de3a29155
--- /dev/null
+++ b/3556/CH4/EX4.6/Ex4_6.sce
@@ -0,0 +1,36 @@
+clc
+// Fundamental of Electric Circuit
+// Charles K. Alexander and Matthew N.O Sadiku
+// Mc Graw Hill of New York
+// 5th Edition
+
+// Part 1 : DC Circuits
+// Chapter 4 : Circuit Theorems
+// Example 4 - 6
+
+clear; clc; close;
+//
+// Given data
+R2 = 2.00000;
+R4 = 4.0000;
+R8 = 8.0000;
+R3 = 3.0000;
+Vs = 12.0000;
+Is1 = 2.0000;
+//
+// Calculations R6 = R2 Series R4
+R6 = R2 + R4;
+// Calculations Is2
+Is2 = Vs/R6;
+// Calculations Rp1 = R3 Parallel R6
+Rp1 = (R6*R3)/(R6+R3);
+// Calculations Vo
+Vo = ((Rp1*R8)/(Rp1+R8))*Is1
+// Display the result
+disp("Example 4-6 Solution : ");
+printf(" \n Vo = Voltage For R 8 ohm = %.3f Volt",Vo)
+
+
+
+
+
diff --git a/3556/CH4/EX4.8/Ex4_8.sce b/3556/CH4/EX4.8/Ex4_8.sce
new file mode 100644
index 000000000..f79b0df3c
--- /dev/null
+++ b/3556/CH4/EX4.8/Ex4_8.sce
@@ -0,0 +1,46 @@
+clc
+// Fundamental of Electric Circuit
+// Charles K. Alexander and Matthew N.O Sadiku
+// Mc Graw Hill of New York
+// 5th Edition
+
+// Part 1 : DC Circuits
+// Chapter 4 : Circuit Theorems
+// Example 4 -
+8
+clear; clc; close;
+//
+// Given data
+R4 = 4.00000;
+R12 = 12.0000;
+R1 = 1.0000;
+Vs = 32.0000;
+Is = -2.0000;
+RL1 = 6.0000;
+RL2 = 16.0000;
+RL3 = 36.0000;
+//
+// Calculations Rth
+Rth1 = (R4*R12)/(R4+R12);
+Rth = R1 + Rth1;
+// Calculations Vth
+I1 = (Vs + (R12*Is))/(R4+R12)
+I2 = Is;
+Vth = R12*(I1-I2)
+// Calculation IL1 for RL = 6 Ohm
+IL1 = Vth/(Rth + RL1)
+// Calculation IL2 for RL = 16 Ohm
+IL2 = Vth/(Rth + RL2)
+// Calculation IL3 for RL = 36 Ohm
+IL3 = Vth/(Rth + RL3)
+// Display the result
+disp("Example 4-8 Solution : ");
+printf(" \n Vth = Voltage Thevenin = %.3f Volt",Vth)
+printf(" \n Rth = Resistance Thevenin = %.3f Ohm",Rth)
+printf(" \n IL1 = Load Current For RL 6 Ohm = %.3f A",IL1)
+printf(" \n IL2 = Load Current For RL 16 Ohm = %.3f A",IL2)
+printf(" \n IL3 = Load Current For RL 36 Ohm = %.3f A",IL3)
+
+
+
+