diff options
Diffstat (limited to '3556/CH4/EX4.8/Ex4_8.sce')
| -rw-r--r-- | 3556/CH4/EX4.8/Ex4_8.sce | 46 |
1 files changed, 46 insertions, 0 deletions
diff --git a/3556/CH4/EX4.8/Ex4_8.sce b/3556/CH4/EX4.8/Ex4_8.sce new file mode 100644 index 000000000..f79b0df3c --- /dev/null +++ b/3556/CH4/EX4.8/Ex4_8.sce @@ -0,0 +1,46 @@ +clc
+// Fundamental of Electric Circuit
+// Charles K. Alexander and Matthew N.O Sadiku
+// Mc Graw Hill of New York
+// 5th Edition
+
+// Part 1 : DC Circuits
+// Chapter 4 : Circuit Theorems
+// Example 4 -
+8
+clear; clc; close;
+//
+// Given data
+R4 = 4.00000;
+R12 = 12.0000;
+R1 = 1.0000;
+Vs = 32.0000;
+Is = -2.0000;
+RL1 = 6.0000;
+RL2 = 16.0000;
+RL3 = 36.0000;
+//
+// Calculations Rth
+Rth1 = (R4*R12)/(R4+R12);
+Rth = R1 + Rth1;
+// Calculations Vth
+I1 = (Vs + (R12*Is))/(R4+R12)
+I2 = Is;
+Vth = R12*(I1-I2)
+// Calculation IL1 for RL = 6 Ohm
+IL1 = Vth/(Rth + RL1)
+// Calculation IL2 for RL = 16 Ohm
+IL2 = Vth/(Rth + RL2)
+// Calculation IL3 for RL = 36 Ohm
+IL3 = Vth/(Rth + RL3)
+// Display the result
+disp("Example 4-8 Solution : ");
+printf(" \n Vth = Voltage Thevenin = %.3f Volt",Vth)
+printf(" \n Rth = Resistance Thevenin = %.3f Ohm",Rth)
+printf(" \n IL1 = Load Current For RL 6 Ohm = %.3f A",IL1)
+printf(" \n IL2 = Load Current For RL 16 Ohm = %.3f A",IL2)
+printf(" \n IL3 = Load Current For RL 36 Ohm = %.3f A",IL3)
+
+
+
+
|