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Diffstat (limited to '3556/CH2/EX2.13')
| -rw-r--r-- | 3556/CH2/EX2.13/Ex2_13.sce | 45 |
1 files changed, 45 insertions, 0 deletions
diff --git a/3556/CH2/EX2.13/Ex2_13.sce b/3556/CH2/EX2.13/Ex2_13.sce new file mode 100644 index 000000000..67c26d2ae --- /dev/null +++ b/3556/CH2/EX2.13/Ex2_13.sce @@ -0,0 +1,45 @@ +clc
+// Fundamental of Electric Circuit
+// Charles K. Alexander and Matthew N.O Sadiku
+// Mc Graw Hill of New York
+// 5th Edition
+
+// Part 1 : DC Circuits
+// Chapter 2: Basic Laws
+// Example 2 - 13
+
+clear; clc; close;
+//
+// Given data
+I = 30.00/1000;
+R6 = 6.00*1000;
+R12 = 12.00*1000;
+R9 = 9.00*1000;
+//
+// Calculations
+// Calculations RP1
+RP1 = (R6 + R12);
+// Calculations current branch 1
+I1 = (RP1/(RP1+ R9))* I;
+// Calculations current branch 2
+I2 = (R9/(RP1 + R9))* I;
+// Calcukations Vo
+Vo = R9*I1
+// Calculatiuons Po
+Po = Vo * I;
+// Calculations P9
+P9 = (I1^2)*R9;
+// Calculations P6
+P6 = (I2^2) * R6;
+// Calculations P12
+P12 = (I2^2) * R12;
+//
+// Display the result
+disp("Example 2-13 Solution : ");
+printf(" \n Vo : Voltage in the 9 Ohm Resistor = %.3f Volt ",Vo);
+printf(" \n Po : Power supllied by the source = %.3f Watt ",Po);
+printf(" \n P9 : Power absorbed in the 9 ohm resistor = %.3f Watt ",P9);
+printf(" \n P6 : Power absorbed in the 6 ohm resistor = %.3f Watt ",P6);
+printf(" \n P12 : Power absorbed in the 12 ohm resistor = %.3f Watt ",P12);
+
+
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