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clc
// Fundamental of Electric Circuit
// Charles K. Alexander and Matthew N.O Sadiku
// Mc Graw Hill of New York
// 5th Edition
// Part 1 : DC Circuits
// Chapter 2: Basic Laws
// Example 2 - 13
clear; clc; close;
//
// Given data
I = 30.00/1000;
R6 = 6.00*1000;
R12 = 12.00*1000;
R9 = 9.00*1000;
//
// Calculations
// Calculations RP1
RP1 = (R6 + R12);
// Calculations current branch 1
I1 = (RP1/(RP1+ R9))* I;
// Calculations current branch 2
I2 = (R9/(RP1 + R9))* I;
// Calcukations Vo
Vo = R9*I1
// Calculatiuons Po
Po = Vo * I;
// Calculations P9
P9 = (I1^2)*R9;
// Calculations P6
P6 = (I2^2) * R6;
// Calculations P12
P12 = (I2^2) * R12;
//
// Display the result
disp("Example 2-13 Solution : ");
printf(" \n Vo : Voltage in the 9 Ohm Resistor = %.3f Volt ",Vo);
printf(" \n Po : Power supllied by the source = %.3f Watt ",Po);
printf(" \n P9 : Power absorbed in the 9 ohm resistor = %.3f Watt ",P9);
printf(" \n P6 : Power absorbed in the 6 ohm resistor = %.3f Watt ",P6);
printf(" \n P12 : Power absorbed in the 12 ohm resistor = %.3f Watt ",P12);
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