diff options
Diffstat (limited to '3554/CH20')
-rw-r--r-- | 3554/CH20/EX20.1/Ex20_1.sce | 15 | ||||
-rw-r--r-- | 3554/CH20/EX20.2/Ex20_2.sce | 18 | ||||
-rw-r--r-- | 3554/CH20/EX20.3/Ex20_3.sce | 13 |
3 files changed, 46 insertions, 0 deletions
diff --git a/3554/CH20/EX20.1/Ex20_1.sce b/3554/CH20/EX20.1/Ex20_1.sce new file mode 100644 index 000000000..16c5732f1 --- /dev/null +++ b/3554/CH20/EX20.1/Ex20_1.sce @@ -0,0 +1,15 @@ +// Exa 20.1
+
+clc;
+clear all;
+
+// Given data
+
+V1=20;// superimposed small AF voltage(V)
+V2=30;//Bridge balance voltage(V)
+R1=100;// Bridge arm resistor(ohms)
+
+// Solution
+
+RF_pwr=(V2^2-V1^2)/(4*R1);
+printf('RF test power = %.2f W \n',RF_pwr);
diff --git a/3554/CH20/EX20.2/Ex20_2.sce b/3554/CH20/EX20.2/Ex20_2.sce new file mode 100644 index 000000000..2ee1741cd --- /dev/null +++ b/3554/CH20/EX20.2/Ex20_2.sce @@ -0,0 +1,18 @@ +// Exa 20.2
+
+clc;
+clear all;
+
+// Given data
+
+M=200;// mass in grams
+Heat =1;//Sp. Heat of water(cal/gm degree)
+T1=30;//Initial temperature (degree Celsius)
+T2=40;//Final temperature (degree Celsius)
+
+// Solution
+
+Pwr_rad=4.18*M*Heat*(T2-T1); // in Watt
+printf(' The power radiated = %.2f kW \n',Pwr_rad/1000);
+
+// The answer in the textbook is mentioned as 8.3 kW but by calculation it comes out to be 8.36 kW.
diff --git a/3554/CH20/EX20.3/Ex20_3.sce b/3554/CH20/EX20.3/Ex20_3.sce new file mode 100644 index 000000000..cd3a49072 --- /dev/null +++ b/3554/CH20/EX20.3/Ex20_3.sce @@ -0,0 +1,13 @@ +// Exa 20.3
+
+clc;
+clear all;
+
+// Given data
+
+Vmax=8;//Maximum value of voltage
+Vmin=2;//minimum value of voltage
+
+//Solution
+SWR=(Vmax+Vmin)/(Vmax-Vmin);//Standing wave ratio
+printf('Standing Wave Ratio = %.2f \n ',SWR);
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