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+// Exa 20.2
+
+clc;
+clear all;
+
+// Given data
+
+M=200;// mass in grams
+Heat =1;//Sp. Heat of water(cal/gm degree)
+T1=30;//Initial temperature (degree Celsius)
+T2=40;//Final temperature (degree Celsius)
+
+// Solution
+
+Pwr_rad=4.18*M*Heat*(T2-T1); // in Watt
+printf(' The power radiated = %.2f kW \n',Pwr_rad/1000);
+
+// The answer in the textbook is mentioned as 8.3 kW but by calculation it comes out to be 8.36 kW.