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Diffstat (limited to '3507/CH14/EX14.9/Ex14_9.sce')
| -rw-r--r-- | 3507/CH14/EX14.9/Ex14_9.sce | 22 |
1 files changed, 22 insertions, 0 deletions
diff --git a/3507/CH14/EX14.9/Ex14_9.sce b/3507/CH14/EX14.9/Ex14_9.sce new file mode 100644 index 000000000..2b1f2a0fb --- /dev/null +++ b/3507/CH14/EX14.9/Ex14_9.sce @@ -0,0 +1,22 @@ +// chapter14
+// example14.9
+// page 303
+
+// figure given in book is for reference only. It is not required to solve the example since the required details are very clearly specified in the problem statement.
+// moreover more data is needed to plot the graph given in book.
+
+Av_max1=2000 // for 2 kHz
+Av_sqrt_2=1414 // for 10 kHz and 50 Hz
+
+percent_Av_max1=70.7*Av_max1/100
+printf("70.7 percent of maximum gain 2000 is = %.3f \n",percent_Av_max1)
+
+if Av_sqrt_2==percent_Av_max1
+printf("we observe that 70.7 percent of max gain 2000 is 1414 \n")
+printf("this gain 1414 is at 50 Hz and 10 kHz \n")
+printf("so bandwidth = 50 Hz to 10 kHz \n \n")
+
+printf("since frequency on lower side at which gain falls to \n70.7 percent is 50 Hz.So lower cutoff frequency = 50 Hz \n \n")
+printf("since frequency on upper side at which gain falls to \n70.7 percent is 10 kHz.So upper cutoff frequency = 10 kHz \n \n")
+else printf("data is insuficient for finding bandwidth and cutoff frequencies \n")
+end
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