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+//chapter12
+//example12.17
+//page253
+
+Vcc=15 // V
+Re=2 // kilo ohm
+Rc=1 // kilo ohm
+gain_beta=100
+Vbe=0.7 // V
+R1=10 // kilo ohm
+R2=5 // kilo ohm
+
+Eo=Vcc*R2/(R1+R2)
+Ro=R1*R2/(R1+R2)
+
+printf("thevenin voltage = %.3f V \n",Eo)
+printf("thevenin resistance = %.3f kilo ohm \n",Ro)
+
+// here Eo=Ib*Ro+Vbe+Ie*Re
+// now considering Ie=gain_beta*Ib, we can replace Ib=Ie/gain_beta
+// Eo=(Ie/gain_beta)*Ro+Vbe+Ie*Re
+// making Ie as subject we get
+Ie=(Eo-Vbe)/(Re+Ro/gain_beta)
+
+printf("emitter current = %.3f mA \n",Ie)