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+//chapter11
+//example11.20
+//page224
+
+Vcc=20 // V
+Rc=1 // kilo ohm
+
+// for saturation collector current, knee voltage becomes 0V so we get
+Ic_sat=Vcc/Rc
+
+// it can be seen from the circuit that cut-off voltage (i.e. when Ib=0) equals Vcc itself
+Vce_cutoff=Vcc
+
+// the equation of load line becomes Ic=-Vce+20
+
+clf()
+x=linspace(0,20,5)
+y=-x+20
+plot2d(x,y,style=3,rect=[0,0,21,21])
+xtitle("dc load line","Vce(volts)","Ic(mA)")
+
+printf("saturation collector current = %.3f mA \n",Ic_sat)
+printf("cut-off collector emitter voltage = %.3f V \n",Vce_cutoff)