diff options
Diffstat (limited to '3472/CH3')
-rw-r--r-- | 3472/CH3/EX3.1/Example3_1.sce | 29 | ||||
-rw-r--r-- | 3472/CH3/EX3.3/Example3_3.sce | 25 | ||||
-rw-r--r-- | 3472/CH3/EX3.4/Example3_4.sce | 26 |
3 files changed, 80 insertions, 0 deletions
diff --git a/3472/CH3/EX3.1/Example3_1.sce b/3472/CH3/EX3.1/Example3_1.sce new file mode 100644 index 000000000..ef07b4ca5 --- /dev/null +++ b/3472/CH3/EX3.1/Example3_1.sce @@ -0,0 +1,29 @@ +// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART I : GENERATION
+// CHAPTER 3: HYDRO-ELECTRIC STATIONS
+
+// EXAMPLE : 3.1 :
+// Page number 41
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+Q = 95.0 // Minimum run-off(m^3/sec)
+h = 40.0 // Head(m)
+
+// Calculations
+w = 1000.0 // Density of water(kg/m^3)
+weight = Q*w // Weight of water per sec(kg)
+work_done = weight*h // Work done in one second(kg-mt)
+kW_1 = 75.0/0.746 // 1 kW(kg-mt/sec)
+power = work_done/kW_1 // Power production(kW)
+hours_year = 365.0*24 // Total hours in a year
+output = power*365*24.0 // Yearly gross output(kWhr)
+
+// Results
+disp("PART I - EXAMPLE : 3.1 : SOLUTION :-")
+printf("\nFirm capacity = %.f kW", power)
+printf("\nYearly gross output = %.2e kWhr.", output)
diff --git a/3472/CH3/EX3.3/Example3_3.sce b/3472/CH3/EX3.3/Example3_3.sce new file mode 100644 index 000000000..f0a304697 --- /dev/null +++ b/3472/CH3/EX3.3/Example3_3.sce @@ -0,0 +1,25 @@ +// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART I : GENERATION
+// CHAPTER 3: HYDRO-ELECTRIC STATIONS
+
+// EXAMPLE : 3.3 :
+// Page number 41
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+A = 200.0 // Catchment area(Sq.km)
+F = 1000.0 // Annual rainfall(mm)
+H = 200.0 // Effective head(m)
+K = 0.5 // Yield factor
+n = 0.8 // Plant efficiency
+
+// Calculations
+P = 3.14*n*K*A*F*H*10**-4 // Available continuous power(kW)
+
+// Results
+disp("PART I - EXAMPLE : 3.3 : SOLUTION :-")
+printf("\nAvailable continuous power of hydro-electric station , P = %.f kW", P)
diff --git a/3472/CH3/EX3.4/Example3_4.sce b/3472/CH3/EX3.4/Example3_4.sce new file mode 100644 index 000000000..a5a7cb173 --- /dev/null +++ b/3472/CH3/EX3.4/Example3_4.sce @@ -0,0 +1,26 @@ +// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART I : GENERATION
+// CHAPTER 3: HYDRO-ELECTRIC STATIONS
+
+// EXAMPLE : 3.4 :
+// Page number 41-42
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+load_factor = 0.15 // Load factor
+P = 10.0*10**3 // Rated installed capacity(kW)
+H = 50.0 // Head of plant(m)
+n = 0.8 // Efficiency of plant
+
+//Calculation
+units_day = P*load_factor // Total units generated daily on basis of load factor(kWhr)
+units_week = units_day*24.0*7 // Total units generated for one week(kWhr)
+Q = units_week/(9.81*H*n*24*7) // Minimum flow of water(cubic mt/sec)
+
+//Result
+disp("PART I - EXAMPLE : 3.4 : SOLUTION :-")
+printf("\nMinimum flow of river water to operate the plant, Q = %.3f cubic mt/sec", Q)
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