1 files changed, 33 insertions, 0 deletions
diff --git a/3472/CH12/EX12.10/Example12_10.sce b/3472/CH12/EX12.10/Example12_10.sce
new file mode 100644
index 000000000..bcb91a03e
--- /dev/null
+++ b/3472/CH12/EX12.10/Example12_10.sce
@@ -0,0 +1,33 @@
+// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION 
+
+// PART II : TRANSMISSION AND DISTRIBUTION
+// CHAPTER 5: MECHANICAL DESIGN OF OVERHEAD LINES
+
+// EXAMPLE : 5.10 :
+// Page number 201-202
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+L = 250.0          // Span(m)
+d = 1.42           // Diameter(cm)
+w = 1.09           // Dead weight(kg/m)
+wind = 37.8        // Wind pressure(kg/m^2)
+r = 1.25           // Ice thickness(cm)
+f_m = 1050.0       // Maximum working stress(kg/sq.cm)
+
+// Calculations
+w_i = 913.5*%pi*r*(d+r)*10**-4          // Weight of ice on conductor(kg/m)
+w_w = wind*(d+2*r)*10**-2               // Wind load of conductor(kg/m)
+w_r  = ((w+w_i)**2+w_w**2)**0.5         // Resultant pressure(kg/m)
+a = %pi*d**2/4.0                        // Area(cm^2)
+T_0 = f_m*a                             // Tension(kg)
+S = w_r*L**2/(8*T_0)                    // Total sag(m)
+vertical_sag = S*(w+w_i)/w_r            // Vertical component of sag(m)
+
+// Results
+disp("PART II - EXAMPLE : 5.10 : SOLUTION :-")
+printf("\nCase(i) : Sag in inclined direction = %.f m", S)
+printf("\nCase(ii): Sag in vertical direction = %.2f m", vertical_sag)