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// A Texbook on POWER SYSTEM ENGINEERING
// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
// DHANPAT RAI & Co.
// SECOND EDITION
// PART II : TRANSMISSION AND DISTRIBUTION
// CHAPTER 5: MECHANICAL DESIGN OF OVERHEAD LINES
// EXAMPLE : 5.10 :
// Page number 201-202
clear ; clc ; close ; // Clear the work space and console
// Given data
L = 250.0 // Span(m)
d = 1.42 // Diameter(cm)
w = 1.09 // Dead weight(kg/m)
wind = 37.8 // Wind pressure(kg/m^2)
r = 1.25 // Ice thickness(cm)
f_m = 1050.0 // Maximum working stress(kg/sq.cm)
// Calculations
w_i = 913.5*%pi*r*(d+r)*10**-4 // Weight of ice on conductor(kg/m)
w_w = wind*(d+2*r)*10**-2 // Wind load of conductor(kg/m)
w_r = ((w+w_i)**2+w_w**2)**0.5 // Resultant pressure(kg/m)
a = %pi*d**2/4.0 // Area(cm^2)
T_0 = f_m*a // Tension(kg)
S = w_r*L**2/(8*T_0) // Total sag(m)
vertical_sag = S*(w+w_i)/w_r // Vertical component of sag(m)
// Results
disp("PART II - EXAMPLE : 5.10 : SOLUTION :-")
printf("\nCase(i) : Sag in inclined direction = %.f m", S)
printf("\nCase(ii): Sag in vertical direction = %.2f m", vertical_sag)
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