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diff --git a/3472/CH10/EX10.15/Example10_15.sce b/3472/CH10/EX10.15/Example10_15.sce new file mode 100644 index 000000000..b1dfecf7d --- /dev/null +++ b/3472/CH10/EX10.15/Example10_15.sce @@ -0,0 +1,39 @@ +// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART II : TRANSMISSION AND DISTRIBUTION
+// CHAPTER 3: STEADY STATE CHARACTERISTICS AND PERFORMANCE OF TRANSMISSION LINES
+
+// EXAMPLE : 3.15 :
+// Page number 145
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+f = 50.0 // Frequency(Hz)
+L = 200.0 // Line length(km)
+l = 1.20*10**-3 // Inductance(H/km)
+c = 8.0*10**-9 // Capacitance(F/km)
+r = 0.15 // Resistance(ohm/km)
+g = 0.0 // Conductance(mho/km)
+
+// Calculations
+z = r+%i*2*%pi*f*l // Total impedance(ohm/km)
+Z = z*L // Total impedance(ohm)
+y = g+%i*2*%pi*f*c // Total susceptance(mho/km)
+Y = y*L // Total susceptance(mho/km)
+gamma_l = (Z*Y)**0.5 // γl
+alpha_l = real(gamma_l) // αl
+beta_l = imag(gamma_l) // βl
+Z_c = (Z/Y)**0.5 // Surge impedance(ohm)
+A = cosh(gamma_l) // Constant
+B = Z_c*sinh(gamma_l) // Constant(ohm)
+C = (1/Z_c)*sinh(gamma_l) // Constant(S)
+D = A // Constant
+
+// Results
+disp("PART II - EXAMPLE : 3.15 : SOLUTION :-")
+printf("\nA = D = %.3f∠%.2f° ", abs(A),phasemag(A))
+printf("\nB = %.2f∠%.3f° Ω", abs(B),phasemag(B))
+printf("\nC = %.2e∠%.3f° S", abs(C),phasemag(C))
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