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+// Material removal rate and cutting force in turning
+clc
+D_o = 10 // diameter in mm
+N = 360 // spindle rpm
+D_i = 9 // machined diameter in mm
+x = 1.75 // axial speed in mm/min
+l = 125 // length in mm
+rate = 4 // specific energy in W-s/mm^3
+printf("\n Example 8.4")
+V_o = %pi*D_o*1e-3*N
+V_i =%pi*D_i*1e-3*N
+d = (D_o-D_i)/2
+f = x*100/N
+mrr = %pi*(D_o-d)*d*f*N
+t = l/(d*N)
+power = rate*mrr/60
+T = power/(2*%pi*N/60) // torque
+F_c = T/((D_o-d)/(2*1000))
+printf("\n Material removal rate is %.2f mm^3/min.",mrr)
+// Answer in book is 2610.08 mm^3/min
+printf("\n Cutting force is %d N.", F_c)
+// Answer in book is 994N
+