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+// Relative energies in cutting
+clc
+t_o = 0.01 // depth in mm
+V = 125 // velocity in m/min
+alpha = 10 // angle i degree
+t_c = 0.014 // depth of cut in mm
+w = 6 // width of cut in mm
+F_c = 55 // force in Kg
+F_t = 25 // force in kg
+printf("\n Example 8.1")
+r = t_o/t_c
+R = sqrt(F_c^2+F_t^2)
+Beta = acos(F_c/R)*180/%pi + alpha
+F = R*(sin(Beta*%pi/180))
+percentage = 100*(F*r/F_c)
+printf("\n Percentage frictional energy is %.1f%%",percentage)
+printf("\n Percentage shear energy is %.1f%%",100-percentage)
+