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Diffstat (limited to '3250/CH3/EX3.8/Ex3_8.sce')
| -rwxr-xr-x | 3250/CH3/EX3.8/Ex3_8.sce | 20 |
1 files changed, 20 insertions, 0 deletions
diff --git a/3250/CH3/EX3.8/Ex3_8.sce b/3250/CH3/EX3.8/Ex3_8.sce new file mode 100755 index 000000000..16904a775 --- /dev/null +++ b/3250/CH3/EX3.8/Ex3_8.sce @@ -0,0 +1,20 @@ +clc +// Given that +Ri = 30 // Inside radius of cup in mm +t = 3 // Thickness in mm +Rb = 40 // Radius of the blank in mm +K = 210 // Shear yield stress of the material in N/mm^2 +Y = 600 // Maximum allowable stress in N/mm^2 +Beta = 0.05 +mu = 0.1// Cofficient of friction between the job and the dies +// Sample Problem 8 on page no. 130 +printf("\n # PROBLEM 3.8 # \n") +Fh = Beta*%pi*(Rb^2)*K +Y_r = (mu*Fh/(%pi*Rb*t))+(2*K*log(Rb/Ri)) +Y_z = Y_r*exp(mu*%pi/2) +F = 2*%pi*Ri*t*Y_z +Y_r_ = Y/exp(mu*%pi/2) +Rp = (Rb/exp((Y_r_/(2*K)) - ((mu*Fh)/(2*%pi*K*Rb*t))))-t +printf("\n Drawing force = %d N, \n Minimum passible radius of the cup which can drawn from the given blank without causing a fracture = %f mm",F,Rp) +// Answer in the book given as 62680 N + |