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+clc
+// Given that
+mu = 0.08// Cofficient of friction between the job and the dies
+Y = 7 // Avg yield stress of the lead in N/mm^2
+h = 6 // Height of die in mm
+L = 150 // Length of the strip in mm
+V1 = 24*24*150 // Volume of the strip in mm^3
+V2 = 6*96*150 // Volume of the die in mm^3
+w= 96 // Weidth of the die in mm
+// Sample Problem 5 on page no. 119
+printf("\n # PROBLEM 3.5 # \n")
+K = Y/sqrt(3)
+x_ = (h/(2*mu))*(log(1/(2*mu)))
+l = w/2
+funcprot(0)
+function p1 = f(x), p1 = (2*K)*exp((2*mu/h)*x),
+endfunction
+I = intg(0,l,f)
+F = 2*(I)
+F_ = F*L
+printf("\n The maximum forging force = %e N",F_)
+
+