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+
+// Ex4_5
+
+clc;
+
+// Given:
+t=5736;// in years
+Nk=16.1;// dis/min
+L=6.022*10^23;
+// Solution:
+k=(0.693*60)/(t*3.16*10^7);
+N1=Nk/k;// atoms per g for C14
+N2=L/12;//
+
+r=(N1*10^12)/N2;// ratio of C14/C12 in atmosphere
+
+printf("The ratio of C14/C12 in atmosphere in 10^-12 is = %f",r)